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vlada-n [284]
3 years ago
11

How to write 10.4 as a mixed number in simplest form?

Mathematics
1 answer:
ki77a [65]3 years ago
3 0
The answer to your question is 10 2/5
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What compatible numbers would you pick to estimate the difference of 777-248?why
vfiekz [6]
I would pick 750 - 250 because that equals 500. You can also prefer using 800 - 250.
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This is what i have so far, but i’m not sure what i need to fix.
ivann1987 [24]

Answer:

it looks good

Step-by-step explanation:

6 0
3 years ago
What are the coordinates of point A? (8, –6) (–6, 8) (6,-8) (-8, –6)
Jlenok [28]

The coordinates of the point A is (7, -5)

<h3>What are the coordinates of the image?</h3>

Now, we are given 4 coordinates which are;

(8, –6)

(–6, 8)

(–5, 7)

(7, –5)

Now, from the image attached, we can see that at point A, the coordinate can be traced to be (7, -5)

Thus, we conclude that the coordinates of the point A is (7, -5)

The correct question is;

What are the coordinates of point A?

(8, –6)

(–6, 8)

(–5, 7)

(7, –5)

Read more about image coordinates at; brainly.com/question/20935031

#SPJ1

4 0
2 years ago
Which equation has a constant of proportionality equal to three
Andreas93 [3]

Answer in Picture :)

4 0
3 years ago
A conical paper funnel of radius 4 and height 6 units is needed to make a good cup of coffee. If this funnel is made out of a se
Nimfa-mama [501]

Answer:

The radius of this circle is 2\sqrt{13} and the central angle of the sector is \theta=\frac{2}{\sqrt{13}}\times360^\circ.

Step-by-step explanation:

Consider the provided information.

If a conical paper funnel is made out of a sector of circle then the radius of the sector becomes the slant height of the cone, and the length of the curved part of the sector becomes the circumference of the base of the cone.

First find the slant height: l=\sqrt{r^2+h^2}

l=\sqrt{4^2+6^2}

l=\sqrt{16+36}

l=2\sqrt{13}

Thus, the radius of the sector is 2\sqrt{13} which is same as the slant height of the cone.

Now, the circumference of the base of the cone is same as the length of the curved part.

C=2\pi r

C=2\pi \times4=8\pi

The length of the curved part = \frac{\theta}{360\circ}\times2\pi r

\frac{\theta}{360\circ}\times2\pi \times2\sqrt{13}=8\pi

\frac{\theta}{360\circ}\times\sqrt{13}=2

\theta=\frac{2}{\sqrt{13}}\times360^\circ

Hence, the radius of this circle is 2\sqrt{13} and the central angle of the sector is \theta=\frac{2}{\sqrt{13}}\times360^\circ.

4 0
4 years ago
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