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sweet-ann [11.9K]
3 years ago
5

This is what i have so far, but i’m not sure what i need to fix.

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

it looks good

Step-by-step explanation:

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HELP ASAP
Marina CMI [18]

Answer:

sdfgfgav

Step-by-step explanation:

7 0
3 years ago
Penny makes 5 liters of applesauce. She saves 0.24 liter for dinner and puts the rest in jars. If each jar holds 0.68 liter, how
In-s [12.5K]

Answer:

Penny can fill eight jars.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ITS URGENT
OlgaM077 [116]

The missing step in this proof is ∠BAC ≅ ∠BDE ⇒ answer D

Step-by-step explanation:

If two triangles are similar by SAS, then their corresponding angles are

equal and the 3rd corresponding sides have constant ratio

In the two triangles ABC and DBE:

  • ∠ABC ≅ ∠DBE
  • \frac{AB}{DB}=\frac{BC}{BE}

Then the two triangles are similar

From similarity:

∠BAC ≅ ∠BDE

∠BCA ≅ ∠BED

∴ The missing step is ∠BAC ≅ ∠BDE

The missing step in this proof is ∠BAC ≅ ∠BDE

Learn more:

You can learn more about triangles in brainly.com/question/3451297

#LearnwithBrainly

8 0
4 years ago
Read 2 more answers
Need help ASAP! Looking for someone to show work, it’s completely fine if you don’t tho!
andreyandreev [35.5K]
D since (-5 x -5) = 25 and (7 x -8) = -56. Add 25 and -56 and your answer is D. -31
5 0
3 years ago
Please help with #1 and explain your answers! Thank you
sashaice [31]

1a) False. A square is never a trapezoid. A trapezoid has only one pair of parallel sides while the other set of opposite sides are not parallel. Contrast this with a square which has 2 pairs of parallel opposite sides.

1b) False. A rhombus is only a rectangle when the figure is also a square. A square is essentially a rhombus and a rectangle at the same time. If you had a Venn Diagram, then the circle region "rectangle" and the circle region "rhombus" overlap to form the region for "square". If the statement said "sometimes" instead of "always", then the statement would be true.

1c) False. Any rhombus is a parallelogram. This can be proven by dividing up the rhombus into triangles, and then proving the triangles to be congruent (using SSS), then you use CPCTC to show that the alternate interior angles are congruent. Finally, this would lead to the pairs of opposite sides being parallel through the converse of the alternate interior angle theorem. Changing the "never" to "always" will make the original statement to be true. Keep in mind that not all parallelograms are a rhombus.

8 0
3 years ago
Read 2 more answers
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