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Greeley [361]
3 years ago
9

A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface are

a of 57 square centimeters. What is the surface area of the regular triangular pyramid?
Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0
57 cm^2 is equal to the lateral surface area, or the three sides in this case.

57/3= 19 cm^2 per side. Because the base is equal to the area of the side, this is the base area.

19+57= 76 cm^2 for sides+ base (total surface area)

Final answer: 76 cm^2
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Find the measure of DB (a curvy line is on top of DB btw)
klasskru [66]

Answer:

Arc DB = 146

x = 5

Step-by-step explanation:

Remark

The relationship between the large arc, the small arc and the intersecting angle is

1/2 (large arc - small arc) = intersecting angle.

Givens

Large arc = 25x + 21

Small arc = 96

5x

Solution

1/2*(25x + 21 - 96) = 5x*2            Multiply both sides by 2

25x + 21 - 96 = 10 x                     Combine      

25x - 75 = 10x                             Subtract 25x from both sides

-75 = 10x - 25x

-15x = -75

x = 5

DB = 25x + 21

DB = 25*5 + 21

DB = 125 + 21

DB = 146

Tell me if this is not in the choices.

5 0
3 years ago
Joyce saved $80 on an item that was 65<br> %<br> off. What was the original price?
Xelga [282]
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7 0
4 years ago
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At age 45, an elephant grows teeth, each weighing 4 kg. About how many pounds do these teeth weigh? Use the conversion factor 1
Step2247 [10]
Thanks for your question!

4*2.2046
<span>8.8184 lb.

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</span>
8 0
3 years ago
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If a+b= -1 then the value of a^3+b^3 - 3ab= ?
Neporo4naja [7]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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kodGreya [7K]
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6 0
4 years ago
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