A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface are
a of 57 square centimeters. What is the surface area of the regular triangular pyramid?
1 answer:
57 cm^2 is equal to the lateral surface area, or the three sides in this case.
57/3= 19 cm^2 per side. Because the base is equal to the area of the side, this is the base area.
19+57= 76 cm^2 for sides+ base (total surface area)
Final answer: 76 cm^2
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Hey!~
Log 5 + Log 2 = 1
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-Lindsey
Answer:
A
Step-by-step explanation:
V= BxHxL divided by 2
6x9x21= 1,134
divided by 2 equals 567yd
F(x) is most likely the f(f(x)x) where f(x) is g(x))f)) and composition can be 69 + 46 which is the total of 137
