Answer:
<em>m∠C = 30° </em>
Step-by-step explanation:
If ΔADB is an equilateral, then m∠A = m∠ADB = m∠DBA = 60°
If ΔDBC isosceles with DB ≅ BC, then m∠C = m∠BDC ;
m∠C + m∠BDC = m∠DBA = 60° ⇒ <em>m∠C = 30°</em>
A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface are
1 answer:
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