1 2/5 - (-3/5)
First, we're going to convert 1 2/5 into an improper fraction.
1 2/5 = 7/5
7/5 - (-3/5)
Subtracting a negative is the same as adding, so the problem will look like:
7/5 + 3/5
The denominators are the same, so we just add the numerators.
The answer is 10/5, or 2.
67 with the remainder of 31 I hope this helps lol
Answer:
Range is always greater than zero.
Step-by-step explanation:
An exponential growth means that the growth rate of a given quantity increases exponentially.
The graph of an exponential function is shown below.
From the above graph, it's quite clear that the range of the function is never negative.
Hence, one characteristic of exponential growth is that the range(y values on the graph) is always greater than zero.


- <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>



<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>


<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>





<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>





Hence, The value of x and y is 2 and 10/3