For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>
Answer:
use Photo math
Step-by-step explanation:
hope this helps good luck
Using the percentile concept, it is found that 10 students scored lower than he did.
<h3>What is the meaning of the percentile of a measure?</h3>
When a measure is in the xth percentile of a data-set, it is greater than x% of the measures and lesser than (100 - x)%.
In this problem, he scored on the 20th percentile, that is, higher than 20% of the 50 students. Then:
0.2 x 50 = 10.
10 students scored lower than he did.
More can be learned about percentiles at brainly.com/question/24495213
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First insight that is useful here is the fact that you can make a side of the fence any multiple of 2 feet, as long as it's at least 4. By taking 4 foot pieces, you can make 4,8,12, and so on. If you start with 6, then take 4 foot pieces, you can make 6,10,14 and so on. You don't need the 8 foot pieces, they're only a convenience.
So, suppose one side is the smallest possible, ie., 4 foot, what must the other side be to satisfy the constraint?
It must be greater than 216/4=54, so at least 56 (remember, only even sizes), and smaller than 480/4=120, so at most 118.
I've plotted all the possible widths and lengths, but there are a lot of them! (See picture, green area).
Selecting which fence sizes you need is possible using the fact that you can create any multiple of 2 starting at 4. I hope this gives you some pointers!
6.8127x10^16
scientific notation because it's simpler and easier to analyze <span />