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Marrrta [24]
3 years ago
13

the perimeter of a rectangular field is (16a+8b-6c) units and one of its side is (5a+3b-4c) find the other side

Mathematics
1 answer:
Jet001 [13]3 years ago
7 0

3a+b+c


The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.

So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:

16a+8b-6c - 2*(5a+3b-4c) =

16a+8b-6c -10a-6b+8c =

6a+2b+2c

half of that is

(6a+2b+2c)/2 = 3a+b+c

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Step-by-step explanation:

Since they are both rectangles, use the area of a rectangle equation to find it which is length times width. What I would do first is find the area of the big rectangle which is 10*15 which is 150. Then I would find the area of the white space which is 6*4 which is 24. Since the white space is not part of the question, subtract 24 from 150 which gets you 126m2. Hope this helps :)

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