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Marrrta [24]
3 years ago
13

the perimeter of a rectangular field is (16a+8b-6c) units and one of its side is (5a+3b-4c) find the other side

Mathematics
1 answer:
Jet001 [13]3 years ago
7 0

3a+b+c


The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.

So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:

16a+8b-6c - 2*(5a+3b-4c) =

16a+8b-6c -10a-6b+8c =

6a+2b+2c

half of that is

(6a+2b+2c)/2 = 3a+b+c

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Answer:

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Step-by-step explanation:

Given:

f(x) = 2x^3-\frac{3}2x

We need to find f(-4).

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f(-4)= 2\times(-4)^3-\frac{3}{2}\times(-4)\\

By using PEDMAS we will solve for exponential function first we get;

Now we know that (-4)^3=-64

So we get;

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3 years ago
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Step-by-step explanation:

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stiks02 [169]

Answer:

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Step-by-step explanation:

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3 0
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