Yes, the sampling distribution is normally distributed because the population is normally distributed.
A sampling distribution is a chance distribution of a statistic obtained from a larger variety of samples drawn from a specific populace. The sampling distribution of a given population is the distribution of frequencies of a variety of various outcomes that would probable occur for a statistic of a populace.
A sampling distribution is a probability distribution of a statistic this is obtained via drawing a huge variety of samples from a particular populace. Researchers use sampling distributions so that you can simplify the technique of statistical inference.
Solution :
mean = μ40
standard deviation σ σ= 3
n = 10
μx = 40
σ x = σ√n = 3/√10 = 0.9487
μ x = 4σ\x = 0.9487
σx = 0.9487
Yes, the sampling distribution is normally distributed because the population is normally distributed.
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Step-by-step explanation:
Given
w(x) = - 3x - 4
Now
w(7) = - 3 * 7 - 4
= - 21 - 4
= - 25
Hope it will help :)❤
Answer: x=8
Step-by-step explanation:
Distribute 5(x) and 5(-2)
-12 + 6x = 6 + 5x + (-10) OR 5x - 10
Flip if you'd like
6x - 12 = 6 + 5x - 10
Combine like terms
6x−12=(5x)+(6+−10)
6x - 12 = 5x - 4
Subtract 5x from both 6 and 5
6x - 5x = 5x - 5x
5x cancels out, so you're left with x, 12, and -4
x - 12 = -4
Add 12 to 12 and -4
12 + 12 = -4 + 12
12 cancels out
-4 + 12 = 8
x = 8
Step-by-step explanation:
Add everything and then equate it to 360 and when you have found x, substitute it in A and B
One solution was found : t ≤ -13 (Last answer choice)
Pull out like factors :
-3t - 39 = -3 • (t + 13)
Divide both sides by -3
Remember to flip the inequality sign:
Solve Basic Inequality :
Subtract 13 from both sides to get t≤−13
