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3 years ago

Help please !!!! Stuck

Mathematics

2 answers:

Doss [256]3 years ago

7 0

If i am correct your answer is B

Verdich [7]3 years ago

7 0

Well all you got to do is add up all the results Sherrie found then divide it by how many you have. So I’m your case it would be 14.

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A bag has 9 marbles in it. 6 of the marbles are Red and 3 of the marbles are Green. What is the ratio probability of pulling a R

Nana76 [90]

Answer:

85%

6:9

Step-by-step explanation:

6 0

2 years ago

After 6 months what would be the simple interest earned on an investment of $5,000 be at 6%.

stiks02 [169]

Answer:

$150

Step-by-step explanation:

I = prt

I = 5000(.06)(.5)

I = 150

8 0

3 years ago

Here is a probability scale

xxMikexx [17]

Answer:

a) e

b) c

c) a

Step-by-step explanation: Look at the number line. 0 shows that it has no probability while C is at 1/2 showing that it could be half-half. Then you can see one under E which means it is bound to happen.

5 0

2 years ago

The product of two rational numbers is (-28/81). If one of them is (-2/3), the find the other.

KatRina [158]

Answer:

The other rational number is $\dfrac{14}{27}$ .

Step-by-step explanation:

First rational number is $\dfrac{-2}{3}$

Let other rational number is $\dfrac{x}{y}$

The product of two rational numbers is $\dfrac{-28}{81}$

According to question,

$\dfrac{x}{y}\times \dfrac{-2}{3}=\dfrac{-28}{81}$

Multiplying both sides by (-3/2) such that,

$\dfrac{x}{y}\times \dfrac{-2}{3}\times \dfrac{-3}{2}=\dfrac{-28}{81}\times \dfrac{-3}{2}\\\\\dfrac{x}{y}=\dfrac{14}{27}$

So, the other rational number is $\dfrac{14}{27}$ .

6 0

2 years ago

Read 2 more answers

If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n st ?

yulyashka [42]

Answer:

A) None

Step-by-step explanation:

1) $s^t$ shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but $3^4 = 81$ is not a factor of nst = 144.

2) $(st)^2$ shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but $(st)^2 = 24^2$ is not a factor of nst = 12*24. In fact, it is a greater number.

3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.

So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.

4 0

3 years ago