Times the whole equation by 15 since the LCM of 3 and 5 is 15.
You get: 5p-3p-6= 60
Rearrange to get: 2p=66
p=33
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
<span>first you set up a proportion 18 over ? = 60 over 100 then cross multiply. 18*100=1800 then divide that by 60 and you get 30 :)</span>
Answer:
E
Step-by-step explanation:
Solution:-
- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.
- The survey team took a sample of size n = 24 students and obtained the following results:
Sample mean ( x^ ) = 12.3 mins
Sample standard deviation ( s ) = 3.2 mins
- The sample taken was random and independent. We can assume normality of the sample.
- First we compute the critical value for the statistics.
- The z-distribution is a function of two inputs as follows:
- Significance Level ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025
Compute: z-critical = z_0.025 = +/- 1.96
- The confidence interval for the population mean ( u ) of walking times is given below:
[ x^ - z-critical*s / √n , x^ + z-critical*s / √n ]
Answer: [ 12.3 - 1.96*3.2 / √24 , 12.3 + 1.96*3.2 / √24 ]
Answer:
h
Step-by-step explanation: j
