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3 years ago

If a person walks 14 mile in 10 minutes, how far will that person walk in one hour?

Mathematics

2 answers:

kicyunya [14]3 years ago

6 0

Answer:

They would walk 84 miles in one hour.

Step-by-step explanation:

14 x 6 (One hour) = 84 miles

Hope this helps ^^

ycow [4]3 years ago

5 0

Answer:

Step-by-step explanation:

because 1 hour equals 60 mins so 6 x 14

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GalinKa [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar

yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total 4+5+6 = 15 bulbs. If we want to select 3 randomly there are K ways of doing this, where K is the combination of 15 elements taken 3 at a time

$K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455$

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

$\frac{270}{455}=0.5934=59.34\%$

(b)

The probability of selecting three 40-W bulbs is

$\frac{4*3*2}{455}=0.0527=5.27\%$

The probability of selecting three 60-W bulbs is

$\frac{5*4*3}{455}=0.1318=13.18\%$

The probability of selecting three 75-W bulbs is

$\frac{6*5*4}{455}=0.2637=26.37\%$

Since the events are disjoint, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

$\frac{6*5*4}{455}=0.2637=26.37\%$

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, supposing there is no replacement, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is $\frac{9}{15}=0.6$

Since there are no replacement, the probability of taking a second non 75-W bulb is now $\frac{8}{14}=0.5714$

Following this procedure 5 times, we find the probabilities

$\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}$

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0

3 years ago

Consider an espresso stand with a single barista. Customers arrive at the stand at the rate of 28 per hour according to a Poisso

Snowcat [4.5K]

Answer:

The average number of customers in the system is 3.2

Step-by-step explanation:

The average number of customes in the system is given by:

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

In which

$\lambda$ is the number of arirvals per time period

$\mu$ is the average number of people being served per period.

The number of arrivals is modeled by the Poisson distribution, while the service time is modeled by the exponential distribution.

Customers arrive at the stand at the rate of 28 per hour

This means that $\lambda = 28$

Service times are exponentially distributed with a service rate of 35 customers per hour.

This means that $\mu = 35$ . So

The average number of customers in the system (i.e., waiting and being served) is

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

$L = \frac{28^{2}}{35(35 - 28)} = 3.2$

The average number of customers in the system is 3.2

4 0

3 years ago

9. What is the system of equations that describes the following graph?

jeka94

The graph represented in the figure shows a set of linear equations each of which is represented a straight line.

Step-by-step explanation:

System of Equation can be referred to as an assortment of equations to be dealt with. Common examples include linear equations and non-linear equations such as a parabola, hyperbola etc.

Linear set of equations are the most simple of equation depicting a linear relationship between two variables.

E.g. Y=4x+3

here y and x share a linear relationship which is defined by the straight-line graph "4x+3"

Similarly in the graph lines, two straight lines are depicted which symbolises that the et of the equation is linear in character.

3 0

4 years ago

If T is the midpoint of SU find the values of x, ST and SU.

Nitella [24]

Answer: The required values are

x = 12 units, ST = 60 units and SU = 120 units.

Step-by-step explanation: Given that T is the midpoint of SU, where

ST = 5x and TU = 3x + 24.