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4 years ago

Jan walks 4 miles each week for one month.how many miles does she walk altogether

Mathematics

2 answers:

AveGali [126]4 years ago

4 0

16 miles if its 4 weeks. its 12 miles if its 3 weeks. its 20 miles if its 5 weeks

solniwko [45]4 years ago

3 0

I think it's 8 miles in one month if you round it I don't know what the exact decimal would be.

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Observa las fracciones y resuelve 12/40 1/8 1/9 1/6 2/10

OLEGan [10]

Explicacion paso a paso:

12/40

Divida tanto el numerador como el denominador por 2.

= 6/20

Divida tanto el numerador como el denominador por 2 neuvamente.

= 3/10 (Esto no se puede simplificar a menos que se cambie a decimal.)

1/8

(Esto no se puede simplificar a menos que se cambie a decimal.)

1/9

(Esto no se puede simplificar a menos que se cambie a decimal.)

1/6

(Esto no se puede simplificar a menos que se cambie a decimal.)

2/10

Divida tanto el numerador como el denominador por 2.

= 1/5 (Esto no se puede simplificar a menos que se cambie a decimal.)

Si esto no es lo que querias, dimelo. Hablo y entiendo ingles. Utilice el traductor de Google para intentar comprender tu pregunta. :)

Si estoy en lo cierto, agradezcalo califique con 5 estrellas y de lo mas Brainliest.

7 0

4 years ago

Consider line segment AB whose endpoints are (1, 4) and (4, 8). If this segment is dilated by a scale factor of 4 centered at th

gulaghasi [49]

Answer:

The length of the new segments A'B' is 20 units ⇒ answer C

Step-by-step explanation:

* Lets revise the dilation

- A dilation is a transformation that changes the size of a figure.

- It can become larger or smaller, but the shape of the figure does

not change.

- The scale factor, measures how much larger or smaller the image

will be

- If the scale factor greater than 1, then the image will be larger

- If the scale factor between 0 and 1, then the image will be smaller

* Lets solve the problem

- line segment AB whose endpoints are (1, 4) and (4, 8) is dilated by

a scale factor of 4 and centered at the origin

∵ The scale factor is 4 and it is greater than 1

- The length of the image of line segment AB will enlarged by the

scale factor 4

∴ A'B' = 4 AB

* Lets find the length of AB by using the rule of the distance

∵ $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

∵ A = $(x_{1},y_{1})$ and B = $(x_{2},y_{2})$

∵ A = (1 , 4) and B = (4 , 8)

∴ $(x_{1},y_{1})=(1 , 4)$ and $(x_{2},y_{2})=(4 , 8)$

∵ AB = $\sqrt{(4-1)^{2}+(8-4)^{2}}=5$

∴ AB = 5 units

∵ A'B' = 4 AB

∴ A'B' = 4 × 5 = 20

∴ The length of the new segments A'B' is 20 units

8 0

3 years ago

A distribution has the five-number summary shown below. What is the

Irina-Kira [14]

Answer:

The interquartile range(IQR) is 31.

Step-by-step explanation:

Given:

A distribution has the five-number summary shown below:

24, 36, 42, 57, 65.

Now, to find the interquartile range (IQR).

So, to get the IQR we need to find the quartile 1 and quartile 3:

As, 42 is the median.

Quartile 1 is the average of first half.

24, 36, 42, 57, 65.

Q1 = $\frac{24+36}{2}$

Q1 = $\frac{60}{2}$

Q1 = $30$

Quartile 3 is the average of last half.

24, 36, 42, 57, 65.

Q3 = $\frac{57+65}{2}$

Q3 = $\frac{122}{2}$

Q3 = $61$

Thus, by putting the formula we get IQR:

IQR = Q3 - Q1.

$IQR=61-30$

$IQR=31.$

Therefore, the interquartile range(IQR) is 31.

4 0

3 years ago

I need help. Whats the answer?

yulyashka [42]

By the pythagorean theorem a^2 + b^2 = c^2 so if we do 8^2 + 6^2 it is 100

3 0

3 years ago

Aiden wants to find the mass of a bowling ball which unit should he use

yaroslaw [1]

He should use pounds.

Explanation:
A bowling ball as we know it is an American item. In Britain, bowling most commonly means "lawn bowling," which uses different equipment. A bowling ball would be for the ten-pin bowling Americans enjoy. Since it is an American sport, we would not use the metric system; instead, we would use pounds.

5 0

3 years ago

Read 2 more answers