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jolli1 [7]
3 years ago
6

How do I solve this?: The times of all 15 year olds who run a certain race are approximately normally distributed with a given m

ean = 18 sec and standard deviation = 1.2 sec. What percentage of the runners have times less than 14.4 sec?

Mathematics
2 answers:
ruslelena [56]3 years ago
6 0

Answer:

0.15%

Step-by-step explanation: i took the test

Effectus [21]3 years ago
5 0
We need to 'standardise' the value of X = 14.4 by first calculating the z-score then look up on the z-table for the p-value (which is the probability)

The formula for z-score:
z = (X-μ) ÷ σ

Where
X = 14.4
μ = the average mean = 18
σ = the standard deviation = 1.2

Substitute these value into the formula

z-score = (14.4 - 18) ÷ 1..2 = -3

We are looking to find P(Z < -3)
The table attached conveniently gives us the value of P(Z < -3)  but if you only have the table that read p-value to the left of positive z, then the trick is to do:
1 - P(Z<3)

From the table
P(Z < -3) = 0.0013

The probability of the runners have times less than 14.4 secs is 0.0013 = 0.13%


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\huge{\boxed{n=-4}}

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\begin{array}{cc}\begin{flushright}\text{Divide both sides of the equation by 3.}\end{flushright}&\begin{flushleft}-4n-9=7\end{flushleft}\\\begin{flushright}\text{Add 9 on both sides.}\end{flushright}&\begin{flushleft}-4n=16\end{flushleft}\\\begin{flushright}\text{Divide both sides by -4.}\end{flushrigh}&n=-4\end{array}

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