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WARRIOR [948]
3 years ago
7

How do you solve 5x-2y= 18 and -5x+3y= -22 by solving a system of linear equations by elimination? Please add the steps in which

you have found out the answer:)
Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0
Write the 2 equations:

5x-2y=18
-5x+3y=-22

You can see that the coefficients of x are opposites, so you can add them(the 2 equations) to eliminate x.

Adding them, you get:

y=-3

So now that you know y, you can substitute the value of y into one of the original equations. Let's substitute it in the first one:

5x+6=18

Solving this, we get:

5x=12
x=12/5

x=12/5, y=-3
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7 0
3 years ago
2^x-1=128<br><br><br> show work pls! thank u :)
hichkok12 [17]

Hello from MrBillDoesMath!

Answer:

Take you pick below!   (either x 8 or x = 7.01, approx, depending how the question is interpreted)




Discussion:

Interpretation 1

If the question is   2^(x -1)  = 128, then as 2^7 = 128,

x-1 = 7 so x = 8



Interpretation 2

If the question is (2^x -1) = 128, then..

2^x  = 128 + 1 = 129  =>

log(2^x) = log(129) =>

xlog(2) = log(129) =>

x = log (129) / log2 = 7.01

Regards,  

MrB

4 0
3 years ago
Justin is training for a hamburger eating competition. He is eventually able to eat 15 hamburgers in 10 minutes. What is justin’
user100 [1]

Answer:

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