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mylen [45]
3 years ago
14

Square root x^5 y^3 z^2 Simplify the following

Mathematics
2 answers:
Bess [88]3 years ago
6 0
Split it all up into "something to the squared".
\sqrt{x^2*x^2+x+y^2+y+z^2}
\sqrt{x^4+x+y^2+y+z^2}
x^2yz\sqrt{x+y}

It, however, is simplified to the furthest.
rewona [7]3 years ago
3 0
That's the furthest it can be simplified.
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Solve: x to the 3rd power equals 1 over 8
kari74 [83]
X should be 1/2
The way I solved this was by viewing 1/8. I grabbed 8 from the equation and did 8^(1/3) which got me 2. In addition both 1/8 and 1/2^3 in decimal form are both 0.125
8 0
3 years ago
Using set notation;
Lostsunrise [7]

Answer:

25.

Step-by-step explanation:

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5 0
3 years ago
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Please help!!!!! <br><br><br> Split using partial fraction decomposition
Rama09 [41]

Answer:

11

Step-by-step explanation:

11

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
Any unknown or changeable quantity is called a (n)
aleksandr82 [10.1K]
There is little context to go off of but the answer should be variable
4 0
4 years ago
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