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2 years ago

Square root x^5 y^3 z^2 Simplify the following

2 answers:

6 0

Split it all up into "something to the squared".
$\sqrt{x^2*x^2+x+y^2+y+z^2}$
$\sqrt{x^4+x+y^2+y+z^2}$
$x^2yz\sqrt{x+y}$

It, however, is simplified to the furthest.

rewona [7]2 years ago

3 0

That's the furthest it can be simplified.

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5. There are 8 sections of seats in an auditorium. Each section contains at least 150 seats but not more than 200 seats. Which o

zaharov [31]

Answer:

1300

Step-by-step explanation:

Given that :

Number of sections = 8

Number of seats per section, x ;

150 ≤ x ≤ 200

The possible Number of seats in the auditorium :

Number of seats per section * number of sections

150 * 8 ≤ x ≤ 200 * 8

1200 ≤ x ≤ 1600

The possible Number of seats will lie within 1200 and 1600

From the options, only 1300 lie within this range

4 0

2 years ago

1. Jordan's washing machine is broken. Since her machine is pretty old, she doesn't want to spend more than $100

ahrayia [7]

Answer:

I think it would be D

Step-by-step explanation:

20 x 3 = 60 60+35= 95 20/4 = 5

4 0

3 years ago

Read 2 more answers

What is the slope-intercept equation of the line below? <br><br><br><br> 10 minutes left

scoray [572]

Answer:

y=-3x+4

Step-by-step explanation:

The y intercept is 4 because the line crosses the y axis at the 4 tic mark

The slope will be -3 because the y decreases by 3 every time the x incerases by 1

y=mx+b

y=-3x+4

7 0

3 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

7 0

3 years ago

What is the difference between a confounding and a lurking variable?

Gennadij [26K]

Answer:

A lurking variable is a variable that has an important effect on the relationship among the variables in the study, but is not one of the explanatory variables studied. Two variables are confounded when their effects on a response variable cannot be distinguished from each other.

4 0

2 years ago

Read 2 more answers