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mylen [45]
3 years ago
14

Square root x^5 y^3 z^2 Simplify the following

Mathematics
2 answers:
Bess [88]3 years ago
6 0
Split it all up into "something to the squared".
\sqrt{x^2*x^2+x+y^2+y+z^2}
\sqrt{x^4+x+y^2+y+z^2}
x^2yz\sqrt{x+y}

It, however, is simplified to the furthest.
rewona [7]3 years ago
3 0
That's the furthest it can be simplified.
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Replace m with a whole number. <br> 7 (4+m)=49
Ann [662]
7*4=28
28+7m=49
49-28=21
7m=21
21/7=3
m=3
3 0
3 years ago
A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea
uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is \mu*n and the standard deviation is s = \sqrt{n}*\sigma

In this question:

n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 6328125}{11250}

X - 6328125 = 1.28*11250

X = 6342525

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0
3 years ago
A contractor is building a fence around a square garden that has a side length of 3 inches in a
Pavel [41]

Answer:

is it adding or subtraction

7 0
2 years ago
What is the value of y in this triangle?
babunello [35]
What triangle? There’s no triangle there.
4 0
3 years ago
Kyle is constructing a bar graph to display the percentage of students enrolled in AP courses from 1996-2005. He is planning to
zepelin [54]
Wheres the bar graph? if its the one with like 1990- 10%
1997- 11%
 then no it wouldn't because the numbers are to close for an increment of 5% it should be more like 1%
7 0
3 years ago
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