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2 years ago

If R = 25 cm and S = 7 cm, what is the length of T?

Mathematics

1 answer:

Levart [38]2 years ago

8 0

Answer: 24cm

Step-by-step explanation:

R = 25 cm

S = 7 cm

T = ?

The square of equals to the addition of the square of S and the square of T.

R^2 = S^2 + T^2

25^2 = 7^2 + T^2

T^2 = 25^2 - 7^2

T^2 = 625 - 49

T =✓576

T = 24cm

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slavikrds [6]

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Step-by-step explanation:

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Answer:

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2 years ago

If the term of arthematic progression decrease in magnitude then common difference must be

Tpy6a [65]

We can say that if the term of arithmetic progression decrease in magnitude then the common difference must be negative.

An arithmetic progression is a sequence where every term is a sum of the previous term and a common difference.

If we suppose the first term of an arithmetic progression to be a, and the common difference to be d, then the arithmetic progression goes like this:

The first term, a₁ = a,

Second term, a₂ = a₁ + d = a + d,

Third term, a₃ = a₂ + d = a + 2d,

Fourth term, a₄ = a₃ + d = a + 3d, and it goes so on up to,

The n-th term, aₙ = aₙ₋₁ + d = a + (n - 1)d.

In the question, we are asked if the term of arithmetic progression decrease in magnitude then what can we say about the common difference.

As the magnitude of the term decreases, we can show that as:

The n-th term < The first term,

or, aₙ < a₁,

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or, a + (n - 1)d - a < a - a {Subtracting a from both sides},

or, (n - 1)d < 0.

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Thus, we can say that if the term of arithmetic progression decrease in magnitude then the common difference must be negative.

Learn more about arithmetic progressions at

brainly.com/question/6561461

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