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emmasim [6.3K]
3 years ago
9

When a projector is placed 10 meters from a screen as shown, it produces an image 3 meters high. If the tallest image that the p

rojector can produce without distortion is 4.5 meters high, what's the maximum distance the projector can be placed form the screen
Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

Answer:

Step-by-step explanation: 10 meters/3 meters =x/4.5 meters

Where x = the maximum distance the projector can be placed that can produce an image 4.5 meters high

3x = 10 (4.5)

3x = 45

X= 45/3

X= 15 meters

So, the maximum distance that the projector can be placed from the screen which produces an image 4.5 meters high is 15 meters.

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Answer:

a) The expected value of M = 40

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b) The expected value of M = 40

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Step-by-step explanation:

* Lets revise some definition to solve the problem

- The mean of the distribution of sample means is called the expected

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- The standard deviation of the distribution of sample means is called

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* lets solve the problem

- A sample is selected from a population

∵ The mean of the population μ = 40

∵ The standard deviation σ = 8

a) The sample has n = 4 scores

∵ The expected value of M = μ

∵ μ = 40

∴ The expected value of M = 40

∵ The standard error of M = σ/√n

∵ σ = 8 and n = 4

∴ σM = 8/√4 = 8/2 = 4

∴ The standard error for M = 4

b) The sample has n = 16 scores

∵ The expected value of M = μ

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∴ The expected value of M = 40

∵ The standard error of M = σ/√n

∵ σ = 8 and n = 16

∴ σM = 8/√16 = 8/4 = 2

∴ The standard error for M = 2

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Step-by-step explanation:

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