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jolli1 [7]
4 years ago
12

The radioisotope Phosphorus-32 is used in leukemia therapy. The half-life of this isotope os 14.26 days. Which equation determin

es the percent of an initial amount of the isotope remaining after t days?
A= 14.26 (1/2)^100/t
A= 14.26(1/2)^t/100
A= 100(1/2)^14.26/t
A= 100(1/2)^t/14.26
Mathematics
1 answer:
larisa [96]4 years ago
3 0
The remaining value= the initial value × (1/2)^(t/T), t is the number of years, T is half life.
So D is the right answer. 
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nydimaria [60]

The Greatest Common Factor (GCF) is very important when factoring. Later on, you will forget to pull out a GCF and the answer will be wrong. Always look for a GCF before doing anything.

Let's try factoring these:

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The greatest common factor of this expression is 9, because it is the maximum number that both can go into. Let's solve.

9(4x+9)

This is the simplest this expression can get. This would be your final answer. Let's try the other one.

b.) 24a+36

The GCF of this one is 12. Let's simplify it.

12(2a+3)

This is also the simplest you can get it. You can do nothing further. So, your final answers are:

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4 years ago
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Dahasolnce [82]

Answer:

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Step-by-step explanation:

Trigonometry ratios:

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I am Lyosha [343]
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aliya0001 [1]
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So you want to pair them up
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You would use the same method if you were going up to a number like a 500
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Answer:the first bowl

Step-by-step explanation:

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2 years ago
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