I beilieve its 3:1. I am not completely sure though
Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
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Answer:
She could make 5 of each type.
Step-by-step explanation:
If x is the number of 0.5 pound hamburgers and y is the number of 0.25 pound hamburgers:
0.5x + 0.25y = 3.75
Divide through by 0.25:
2x + y = 15
Some whole numbers which fit this relation are x = 5 and y = 5.
Answer:
answer below
Step-by-step explanation:
in this case the decimal will be recurring so 1 and 2 thirds is 1.6 recurring and 2 and 7 nigths is 2.7 recurring so just plot in between the intervals so the first one could be between 1.6 and 1.7 and the sexond between 2.7 and 2.8
B.) If two angles of one triangle are equal to two angles of another triangle, then the triangles are similar because of the "<span>ASA Similarity Postulate"
Hope this helps!</span>
