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AleksAgata [21]

2 years ago

8

A triangle with area 195 square inches has a height that is one less than four times the base. Find the base and the height of t

he triangle.

2 answers:

antoniya [11.8K]2 years ago

7 0

Answer:

Bace is 10 and hight is 39.

Step-by-step explanation:

Savatey [412]2 years ago

5 0

Answer:

base = 85 square inches

Step-by-step explanation:

hienght 39 square inches plz give me the brailiest

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This system of equations has A. exactly one solution B. no solution C. infinitely many solution

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C.

Step-by-step explanation:

This is because both lines are parallel, leaving infinite solutions.

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3 years ago

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Select the simplification that accurately explains the following statement.

lutik1710 [3]

Answer:

Option (b) is correct.

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2$

Step-by-step explanation:

Given: $(2^\frac{1}{4} )^4$

We have too choose the correct simplification for the given statement.

Consider $(2^\frac{1}{4} )^4$

Using property of exponents, $(a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)$

We have,

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}$

Again applying property of exponents $a^m\times a^m=a^{n+m}$

We have,

$(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}$

Simplify, we have,

$(2^\frac{1}{4} )^4=2^{\frac{4}{4}}$

we get,

$(2^\frac{1}{4} )^4=2^{1}=2$

Thus, $(2^\frac{1}{4} )^4=2$

Option (b) is correct.

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3 years ago

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Use algebraic means to show that x^2 + y^2 = 8 is not a function. Explain your process.

11Alexandr11 [23.1K]

Answer:

For a single value of x function has more than one corresponding value of y which satisfies the equation.

Step-by-step explanation:

Function: A relationship between a set of inputs and a set of possible outputs, where exactly one output is associated with each input.

It means for an equation to represent a function any single value of x there should be only one corresponding value of y which satisfies the equation.

Now consider the given equation.

$x^2 + y^2 = 8$

If we put x=0 then we get two value of y i.e $\sqrt8$ and $-\sqrt8$ which satisfy the equation and therefore the equation is not a function.

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3 years ago