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3 years ago

ILL GIVE YOU A BRAINLIEST BUT ONLY IF YOURE RIGHT EVERYONE WHO HAS ANSWERED THIS QUESTION HAVE ALL BEEN WRONG SO PLEASE HELP

Mathematics

1 answer:

UkoKoshka [18]3 years ago

4 0

Number 1: a2=3-4=-1

Number 2: a2=-5-4=-9

Number 3: a2=-1-4=-5

Number 4: a1=3

Answer is =-1,-9,-5,3

Hope this helps:)

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If someone could please help me on this it would be amazing thank you so much

ohaa [14]

Answer:

7 cm squared

Step-by-step explanation:

not sure if its right but thats what i got round up to

8 0

3 years ago

A 4-foot tall child walks directly away from a 12-foot tall lamppost at 2 mph. How quickly is the length of her shadow increasin

xz_007 [3.2K]

Answer:

The length of the shadow is increasing with the rate of 1.5 feet per sec

Step-by-step explanation:

Let AB and CD represents the height of the lamppost and child respectively ( shown below )

Also, let E be a point represents the position of child.

In triangles ABE and CDE,

$\angle ABE\cong \angle CDE$ ( right angles )

$\angle AEB\cong \angle CED$ ( common angles )

By AA similarity postulate,

$\triangle ABE\sim \triangle CDE$

∵ Corresponding sides of similar triangles are in same proportion,

$\implies \frac{AB}{CD}=\frac{BE}{DE}$

We have, AB = 12 ft, CD = 4 ft, BE = BD + DE = 6 + DE,

$\implies \frac{12}{4}=\frac{6+DE}{DE}$

$12DE = 24 + 4DE$

$8DE = 24$

$DE=3$

Now, the speed of walking = 2 mph = $\frac{2\times 5280}{3600}\approx 2.933\text{ ft per sec}$

Note: 1 mile = 5280 ft, 1 hour = 3600 sec

Thus, the time taken by child to reach at E

$= \frac{\text{Walked distance}}{\text{Walking speed}}$

$=\frac{6}{2.933}$

= 2.045 hours

Hence, the change rate in the length of shadow

$= \frac{\text{Length of shadow}}{\text{Time taken}}$

$=\frac{3}{2.045}$

= 1.5 ft per sec.

3 0

3 years ago

3. f(x) = – 2 x + 1

KATRIN_1 [288]

Answer:

The quadratic x2 − 5x + 6 factors as (x − 2)(x − 3). Hence the equation x2 − 5x + 6 = 0

has solutions x = 2 and x = 3.

Similarly we can factor the cubic x3 − 6x2 + 11x − 6 as (x − 1)(x − 2)(x − 3), which enables us to show that the solutions of x3 − 6x2 + 11x − 6 = 0 are x = 1, x = 2 or x = 3. In this module we will see how to arrive at this factorisation.

Polynomials in many respects behave like whole numbers or the integers. We can add, subtract and multiply two or more polynomials together to obtain another polynomial. Just as we can divide one whole number by another, producing a quotient and remainder, we can divide one polynomial by another and obtain a quotient and remainder, which are also polynomials.

A quadratic equation of the form ax2 + bx + c has either 0, 1 or 2 solutions, depending on whether the discriminant is negative, zero or positive. The number of solutions of the this equation assisted us in drawing the graph of the quadratic function y = ax2 + bx + c. Similarly, information about the roots of a polynomial equation enables us to give a rough sketch of the corresponding polynomial function.

As well as being intrinsically interesting objects, polynomials have important applications in the real world. One such application to error-correcting codes is discussed in the Appendix to this module.

8 0

3 years ago

Read 2 more answers

Evan says that the value of the numerical expression 0.2+ 12 ÷ (1.5×4) is 32.04 . do you agree ?

12345 [234]

Answer:

NO! The correct answer is 2.03 (where 3 is repeating)

Step-by-step explanation:

0.2 + 12 / (1.5*4) does not equal 32.04

Parenthesis first! 1.5 times 4 equals 6.

0.2 + 12 = 12.2

12.2/6

12.2/6= 2.0333... but it should be rounded to 2, because

3 0

3 years ago

3k-5=20k solve the following equation for k

Virty [35]

Answer:

K = 8.3 repeating or 8 1/3

Step-by-step explanation:

3k - 5 = 20

Add 5 to the '-5' and 20 so you'll now have 3k = 25 (You're isolating the variable )

3k/3 = k

25/3 = 8.3 repeating or 8 1/3

K = 8 1/3 or 8.3 repeating.

4 0

4 years ago