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pantera1 [17]
3 years ago
11

If someone could please help me on this it would be amazing thank you so much

Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

7 cm squared

Step-by-step explanation:

not sure if its right but thats what i got round up to

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bright pools is building a rectangular pool at a new house. The perimeter of the pool has to be 94 feet and the length has to be
bekas [8.4K]

Answer:

\displaystyle 15\:feet\:wide \\ 32\:feet\:long

Step-by-step explanation:

{2 + 2w = l

{94 = 2w + 2l

94 = 2w + 2[2 + 2w]

94 = 2w + 4 + 4w

94 = 4 + 6w

- 4 - 4

_________

\displaystyle \frac{90}{6} = \frac{6w}{6}

\displaystyle 15 = w[Plug this back into both equations above to get the length of 32 feet]; \displaystyle 32 = l

I am joyous to assist you anytime.

4 0
3 years ago
Which set of numbers could represent the lengths of the sides of a right triangle? 16, 32, 36 5, 12, 13 6, 7, 8 8, 12, 16
Elden [556K]

5,12,13

5X5=25

12X12=144

25+144=169

answer: square root 169=13

6 0
3 years ago
Use an area model or the distributive property. <br> (4x +5)(4x-5)
alexandr1967 [171]

Answer:

16x-35

Step-by-step explanation:

Firstly, take the 4x in the first parenthesis and multiply it by the 4x and the -5 in the second parenthesis.

Second, multiply the +5 by the 4x and the -5 in the second parenthesis.

Finally, take both answers and add them together.

3 0
3 years ago
Write the measure -128 30’ 45’’ as a decimal to the nearest thousandth
Zielflug [23.3K]

Answer:

-127.488°

Step-by-step explanation:

45" is 0.75 of 1', so -128° 30' 45" = -128° 30.75'

Next:  30.75' is 30.75/60 of 1°, and or -128° plus 0.5125 of 1°.

The final answer is found by adding 0.5125° to -128°:

 -128.0000°

 +   0.5125°

--------------------

 -127.4875

To the nearest thousandths of a degree, that would be -127.488°

6 0
3 years ago
Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probabili
Gemiola [76]

Answer:

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851</em>

Step-by-step explanation:

<u>step(i)</u>:-

<em>Let 'X' be the random Normal variable</em>

<em>mean of the Population = 365.45</em>

<em>Standard deviation of the population = 4.9 cm</em>

<em>Let X₁ =  360</em>

<em></em>Z= \frac{x-mean}{S.D}= \frac{360-365.45}{4.9}<em></em>

<em>Z₁ = -1.112</em>

<em>Let X₂ =  370</em>

<em></em>Z= \frac{x-mean}{S.D}= \frac{370-365.45}{4.9}<em></em>

<em>Z₂ = 0.911</em>

<u><em>Step(ii</em></u><em>):-</em>

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm</em>

<em>                   P(x₁≤x≤x₂) =    P(z₁≤Z≤z₂) </em>

<em>                P(360 ≤X≤370)   =    P(-1.11≤Z≤0.911)</em>

<em>                                      =    P(Z≤0.911)-P(Z≤-1.11)</em>

<em>                                      =   0.5 +A(0.911) - (0.5-A(1.11)</em>

<em>                                        =    0.5 +A(0.911) - 0.5+A(1.11)</em>

<em>                                       =     A(0.911) + A(1.11)</em>

<em>                                     =    0.3186 + 0.3665</em>

<em>                                      = 0.6851</em>

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851</em>

<em></em>

<em></em>

5 0
3 years ago
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