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pantera1 [17]
3 years ago
11

If someone could please help me on this it would be amazing thank you so much

Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

7 cm squared

Step-by-step explanation:

not sure if its right but thats what i got round up to

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Mr.Dow lives 16 miles from his workplace he drives to and from work five days a week if his car gets 19.2 miles per gallon how m
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Answer:he would require 8.33 gallons of gas

Step-by-step explanation:

Mr Dow lives 16 miles from his workplace he drives to and from work five days a week. It means that the distance that he drives everyday to and from work would be

16 × 2 = 32 miles.

Then, the total distance that he drives in a week to and from work would be

32 × 5 = 160 miles

if his car gets 19.2 miles per gallon, it means that the amount of gas that he would use in one week, commuting to and from work would be

160/19.2 = 8.33 gallons

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3 years ago
According to Greg, perfect cherry pies have a ratio of 240 cherries to 3 pies. How many cherries does Greg need to make 9 perfec
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Simple, 3 goes in to 9, 3 times.  That would mean that to find the number of cherries, multiply 240 by 3.  Greg needs 720 cherries for 9 perfect cherry pies.
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Which scatter plot represents the data shown in the table?​
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The third graph represents the data because the values in the table are identical to the ones plotted on that graph.

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Aaron designed a robot for a contest. His robot can move 3/4 feet in 1/2 second. What is the robot’s unit rate of speed in miles
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Step-by-step explanation:

8 0
3 years ago
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de
attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: \frac{x}{12\pi } = \frac{130}{360}

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) \frac{arclength}{2\pi.r } = \frac{mAB}{360}, where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = \frac{mAB.2.\pi.r }{360}

arc length = \frac{90.2.3.14.6}{360}

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

\frac{x}{2.6.\pi } = \frac{130}{360}

\frac{x}{12\pi } = \frac{130}{360}

c) Resolving (b):

x = \frac{130.12.3.14}{360}

x = 13.6

The arc length for the image is 13.6 inches.

6 0
3 years ago
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