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3 years ago

If someone could please help me on this it would be amazing thank you so much

Mathematics

1 answer:

ohaa [14]3 years ago

8 0

Answer:

7 cm squared

Step-by-step explanation:

not sure if its right but thats what i got round up to

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bright pools is building a rectangular pool at a new house. The perimeter of the pool has to be 94 feet and the length has to be

bekas [8.4K]

Answer:

$\displaystyle 15\:feet\:wide \\ 32\:feet\:long$

Step-by-step explanation:

{2 + 2w = l

{94 = 2w + 2l

94 = 2w + 2[2 + 2w]

94 = 2w + 4 + 4w

94 = 4 + 6w

- 4 - 4

_________

$\displaystyle \frac{90}{6} = \frac{6w}{6}$

$\displaystyle 15 = w$ [Plug this back into both equations above to get the length of 32 feet]; $\displaystyle 32 = l$

I am joyous to assist you anytime.

4 0

3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle? 16, 32, 36 5, 12, 13 6, 7, 8 8, 12, 16

Elden [556K]

5,12,13

5X5=25

12X12=144

25+144=169

answer: square root 169=13

6 0

4 years ago

Use an area model or the distributive property. (4x +5)(4x-5)

alexandr1967 [171]

Answer:

16x-35

Step-by-step explanation:

Firstly, take the 4x in the first parenthesis and multiply it by the 4x and the -5 in the second parenthesis.

Second, multiply the +5 by the 4x and the -5 in the second parenthesis.

Finally, take both answers and add them together.

3 0

3 years ago

Write the measure -128 30’ 45’’ as a decimal to the nearest thousandth

Zielflug [23.3K]

Answer:

-127.488°

Step-by-step explanation:

45" is 0.75 of 1', so -128° 30' 45" = -128° 30.75'

Next: 30.75' is 30.75/60 of 1°, and or -128° plus 0.5125 of 1°.

The final answer is found by adding 0.5125° to -128°:

-128.0000°

+ 0.5125°

--------------------

-127.4875

To the nearest thousandths of a degree, that would be -127.488°

6 0

3 years ago

Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probabili

Gemiola [76]

Answer:

The probability of the length of a randomly selected Cane being between 360 and 370 cm P(360 ≤X≤370) = 0.6851

Step-by-step explanation:

step(i):-

Let 'X' be the random Normal variable

mean of the Population = 365.45

Standard deviation of the population = 4.9 cm

Let X₁ = 360

$Z= \frac{x-mean}{S.D}= \frac{360-365.45}{4.9}$

Z₁ = -1.112

Let X₂ = 370

$Z= \frac{x-mean}{S.D}= \frac{370-365.45}{4.9}$

Z₂ = 0.911

Step(ii):-

The probability of the length of a randomly selected Cane being between 360 and 370 cm

P(x₁≤x≤x₂) = P(z₁≤Z≤z₂)

P(360 ≤X≤370) = P(-1.11≤Z≤0.911)

= P(Z≤0.911)-P(Z≤-1.11)

= 0.5 +A(0.911) - (0.5-A(1.11)

= 0.5 +A(0.911) - 0.5+A(1.11)

= A(0.911) + A(1.11)

= 0.3186 + 0.3665

= 0.6851

The probability of the length of a randomly selected Cane being between 360 and 370 cm P(360 ≤X≤370) = 0.6851

5 0

3 years ago