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posledela
3 years ago
9

This year, the Start-of-Term feast had three desserts: chocolate eclairs, raspberry tarts, and jam doughnuts. On the dessert tab

le, there were two doughnuts for every three eclairs, and six eclairs for every five tarts. How many tarts were on the dessert table if there were a total of 1320 desserts?
Mathematics
2 answers:
Nostrana [21]3 years ago
7 0
Let
 x = chocolate eclairs
 y = raspberry tarts
 z = jam donuts
 We write the following system of equations:
 z = (2/3) x
 x = (6/5) y
 x + y + z = 1320
 Solving for y:
 z = (2/3) (6/5) y
 z = (4/5) y
 then
 (6/5) y + y + (4/5) y = 1320
 3y = 1320
 y = 1230/3 = 410
 answer
 there were 410 tarts on the dessert table
almond37 [142]3 years ago
4 0
<span>Each unit of dessert consists of five tarts, six eclairs and four doughnuts (since there are two for every three eclairs, or four for six). Each unit is therefore 15 deserts. 1320 deserts is 88 units. Each unit has five tarts, so the number of tarts is 88 times 5, or 440.</span>
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