What is the nearest ten thousand rounded to 836527
2 answers:
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Answer:
$291,016.80
A is correct.
Step-by-step explanation:
You are applying for an 80/20 mortgage to buy a house costing $145,000.
Loan Formula:
Case 1:
Loan amount, P = 80% of 145000 = $ 116,000
Rate of interest, r = 4.75% = 0.0475
Time of loan, n = 30 years = 360 months
Substitute the values into formula.
Total payment for case 1: 605.11 x 360 = $217,839.60
Case 2:
Loan amount, P = 20% of 145000 = $ 29,000
Rate of interest, r = 4.75% = 0.07525
Time of loan, n = 30 years = 360 months
Substitute the values into formula.
Total payment for case 1: 203.27 x 360 = $73,177.20
Total amount of the mortgage = $217,839.60 + $73,177.20
= $291,016.80
Hence, The total amount of the mortgage is $291,016.80
Answer:
(- 2, 6 )
Step-by-step explanation:
Given the equations
3x + 2y = 6 → (1)
y - x = 6 ( multiply through by 3 to clear the fraction )
2y - 3x = 18 ( add 3x to both sides )
2y = 18 + 3x → (2)
Substitute 2y = 18 + 3x into (1)
3x + 18 + 3x = 6
6x + 18 = 6 ( subtract 18 from both sides )
6x = - 12 ( divide both sides by 6 )
x = - 2
Substitute x = - 2 into (1) and solve for y
3(- 2) + 2y = 6
- 6 + 2y = 6 ( add 6 to both sides )
2y = 12 ( divide both sides by 2 )
y = 6
solution is (- 2, 6 )
- x-y-z
- YZ=5a=5(5)=25