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3 years ago

Which calculation results in the best estimate of 148 % of 203

Mathematics

2 answers:

adoni [48]3 years ago

6 0

203---- 100%
x-----148%
x=203*148/100=203*1.48=300.44

SVEN [57.7K]3 years ago

3 0

Answer:

300.44 i think lol

Step-by-step explanation:

hope this helps

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Simplify completely quantity x squared minus 3 x minus 54 over quantity x squared minus 18 x plus 81 times quantity x squared pl

oee [108]

Your statemtent is incomplete.

I found the samestatment with the complete words: <span>Simplify completely quantity x squared minus 3 x minus 54 over quantity x squared minus 18 x plus 81 times quantity x squared plus 12 x plus </span>36 over x plus 6

Given that your goal is to learn an be able to solve any similar problem, I can teach you assuming that what I found is exactly what you need.

x^2 - 3x - 54          x^2 + 12x + 36
------------------    x   ---------------------
x^2 - 18x + 81              x + 6

factor x^2 - 3x - 54 => (x - 9)(x + 6)

factor x^2 - 18x + 81 => (x - 9)^2

factor x^2 + 12x + 36 = (x + 6)^2

Now replace the polynomials with the factors=>

(x - 9) (x + 6) (x + 6)^2        (x + 6)^2       x^2 + 12x + 36
------------------------------ = --------------- = --------------------
    (x - 9)^2 (x + 6)                 (x - 9)               x - 9

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alex wong basketball after making a half court shot. the display box for his new basketball is in the shape of a cube. alex meas

suter [353]

408.454 cubic inches of air is surrounding the ball in the box

Step-by-step explanation:

When a sphere is inscribed in a cube and touching all of its faces, then

The diameter of the sphere = the side of the cube
The empty volume of the cube is the difference between the volume of the cube and the volume of the sphere

∵ The basketball is shaped a sphere

∵ The box is shaped a cube

∵ The ball touching every wall of the box

∴ The diameter of the ball = the side of the box

∵ The length of one side of the cube = 9.5 inches

∴ The diameter of the ball = 9.5 inches

∵ The diameter of the ball = 2 r, where r is the radius of the ball

∴ 9.5 = 2 r

- Divide both sides by 2

∴ r = 4.75 inches

∵ The volume of the air that surrounded the ball in the box =

volume of the box - volume of the ball

∵ Volume box (cube) = s³

∵ s = 9.5 inches

∴ Volume of the box = (9.5)³

∴ Volume of the box = 857.375 inches³

∵ Volume the ball (sphere) = $\frac{4}{3}$ π r³

∵ r = 4.75

∴ Volume the ball = $\frac{4}{3}$ (π)(4.75)³

∴ Volume the ball = 448.921 inches³

Substitute the values of the volumes of the box and the ball in the rule above

∴ The volume of the air = 857.375 - 448.921

∴ The volume of the air = 408.454 inches³

408.454 cubic inches of air is surrounding the ball in the box

Learn more:

You can learn more about volume of solids in brainly.com/question/12497249

#LearnwithBrainly

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