What is the measure of ∠w, rounded to the nearest degree? 19° 19° 32° 32° 56° 56° 71° 71° a horizontally-aligned scalene triangl
1 answer:
Answer:
(d) 71°
Step-by-step explanation:
The desired angle in the given isosceles triangle can be found a couple of ways. The Law of Cosines can be used, or the definition of the sine of an angle can be used.
<h3>Sine</h3>Since the triangle is isosceles, the bisector of angle W is an altitude of the triangle. The hypotenuse and opposite side with respect to the divided angle are given, so we can use the sine relation.
sin(W/2) = Opposite/Hypotenuse
sin(W/2) = (35/2)/(30) = 7/12
Using the inverse sine function, we find ...
W/2 = arcsin(7/12) ≈ 35.685°
W = 2×36.684° = 71.37°
W ≈ 71°
<h3>Law of cosines</h3>The law of cosines tells you ...
w² = u² +v² -2uv·cos(W)
Solving for W gives ...
W = arccos((u² +v² -w²)/(2uv))
W = arccos((30² +30² -35²)/(2·30·30)) = arccos(575/1800) ≈ 71.37°
W ≈ 71°
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Answer:
y = - 2x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 8, 22) and (x₂, y₂ ) = (3, 0)
m = =
= - 2, thus
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 0), then
0 = - 6 + c ⇒ c = 0 + 6 = 6
y = - 2x + 6 ← equation of line
<h3>Answer:</h3>
In this question, it's asking you to find how much percentage the circle graph is for "A" papers.
To solve this question, we would need to use information from the question.
Important information:
- Graded 50 English research papers
- 12 of those papers had an "A" grade
With the information above, we can solve the question.
We know that there are 12 research papers that received an A and there are 50 research papers in total.
We would divide 12 by 50 in order to find the percentage of the papers that got an A.
When you divide, you should get 24.
This means that 24% of the circle graph is devoted to "A" papers.
<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>