I did click on the picture but I can't see the problems it is zoomed in.
at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.
![A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill](https://tex.z-dn.net/?f=A%3D700%5Cleft%28%201%20%2B%20%5Cfrac%7B0.05%7D%7B1%7D%20%5Cright%29%5E%7B1%5Ccdot%203%7D%5Cimplies%20A%20%3D%20700%281%2B0.05%29%5E3%5Cimplies%20A%284%29%3D700%281%2B0.05%29%5E%7B4-1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20A%28n%29%3D700%281%2B0.05%29%5E%7Bn-1%7D~%5Chfill)
Do the vertical line test
16. Function
17. Not
18. Not
19. Function
Answer:
4
Step-by-step explanation:
47 - 43 = 4
Step-by-step explanation:
if u mean (x^3 -6x^2 -x- 6) then the answer is C
(6,-1,1)
..................,..........
but if u mean P(x) = x3 – 6x2 – x +62
then the answer is None of the above
-2.724
4.361+1.9328i
4.361+1.9328i
