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Ira Lisetskai [31]
3 years ago
10

Can anyone help me on the last question?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

<h2>           0.7</h2>

Step-by-step explanation:

A' is everything what is not A

So:

    A' = {9, 10, 11, 12, 13, 15, 16}

Number of ways it can happen: |A'| = 7

Total number of outcomes: |Ω| = 10

Probability of an event happening:

                                         \bold{P(A')=\dfrac{|A'|}{|\Omega|}=\dfrac7{10}=0.7}

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2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

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2 years ago
A survey of 163 persons was conducted at TCC, and it was found that 90 persons carried a cell phone, 81 persons carried a tablet
kirza4 [7]

1. The number of people who carried a cell phone or a tablet is <u>128</u>.

2. The probability that a person carries a cell phone or a tablet is <u>78.5%</u>.

3. The number of people who carried neither a cell phone nor a tablet is <u>35</u>.

4. The probability that a person carried neither a cell phone nor a tablet is <u>21.5%</u>.

5. The number of people who carried a cell phone only is <u>43</u>.

6. The probability that a person carried a cell phone only is <u>26.4%</u>.

7. The number of people who carried a tablet but not a cell phone is <u>38</u>.

8. The probability that a person carried a tablet but not a cell phone is <u>23.3%</u>.

<h3>Data and Calculations:</h3>

The sample size of the survey = 163

The number of persons who carried a cell phone = 90

The number of persons who carried a tablet computer = 81

The number of persons who carried both a cell phone and a tablet = 43

1. The number of people who carried a cell phone or a tablet is 128 (90 + 81 - 43).

2. The probability that a person carries a cell phone or a tablet is 78.5%. (128/163).

3. The number of people who carried neither a cell phone nor a tablet is 35 (163 - 128).

4. The probability that a person carried neither a cell phone nor a tablet is 21.5% (35/163).

5. The number of people who carried a cell phone only is 43.

6. The probability that a person carried a cell phone only is 26.4%(43/163).

7. The number of people who carried a tablet but not a cell phone is 38 (81 - 43).

8. The probability that a person carried a tablet but not a cell phone is 23.3% (38/163).

Learn more about probability at brainly.com/question/13604758

#SPJ1

<h3>Question Completion:</h3>

1. How many people carried a cell phone or a tablet?

2. What is the probability that a person carries a cell phone or a tablet?

3. How many people carried neither a cell phone nor a tablet?

4. What is the probability that a person carried neither a cell phone nor a tablet?

5. How many people carried a cell phone only?

6. What is the probability that a person carried a cell phone only?

7. How many people carried a tablet but not a cell phone?

8. What is the probability that a person carried a tablet but not a cell phone?

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