Answer:
The single logarithm is ㏒2[x³/(3/x+4)] ⇒ 1st answer
Step-by-step explanation:
* Lets revise some rules of the logarithmic functions
- log(a^n) = n log(a)
- log(a) + log(b) = log(ab)
- log(a) - log(b) = log(a/b)
* Lets solve the problem
∵ 3㏒2(x) - {㏒2(3) - ㏒2(x + 4)} ⇒ we want to make it single logarithm
# 3㏒2(x) = ㏒2(x³)
# ㏒2(3) - ㏒2(x + 4) = ㏒2[3/(x + 4)]
∴ 3㏒2(x) - {㏒2(3) - ㏒2(x + 4)} = ㏒2(x³) - ㏒2[3/(x + 4)]
∵ ㏒2(x³) - ㏒2[3/(x + 4)] = ㏒2[x³ ÷ 3/(x + 4)]
∴ 3㏒2(x) - {㏒2(3) - ㏒2(x + 4)} = ㏒2[x³/(3/x+4)]
* The single logarithm is ㏒2[x³/(3/x+4)]
TM=MQ
3x+5=x+17
-x -x
___________
2x+5=17
-5 -5
__________
2x=12
__ __
2x 2x
the answer is x=6
Answer:
woow there are so many numbers i dont understand no wonder why u need help
A increase in price increases the quantity of a item .
Answer:
Product 3
Step-by-step explanation:
You can easily find it out based on the last column (Year 3)... where product 3 has the highest market value.
This is very logical due to exponential nature of the price evolution function... it might start lower than most of the other products, but it will grow at a much faster rate... so much that in second year, it's already tie for the most market value.
In year 3, the difference is obvious and it would be even bigger in the following years.
