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victus00 [196]
3 years ago
12

How do I solve this lol

Mathematics
1 answer:
Olin [163]3 years ago
7 0
I would plug the X values into the X spot in your equation and plug in your Y values into the Y spot and dove the equation from there. That pretty much all of the advice I can give for you didn’t provide the actual question but I hope the helped!
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Solve the following quadratic equation 6x^2-5x-4=0
jeka94

Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

6

2

−

5

−

4

=

0

6x^{2}-5x-4=0

6x2−5x−4=0

=

6

a={\color{#c92786}{6}}

a=6

=

−

5

b={\color{#e8710a}{-5}}

b=−5

=

−

4

c={\color{#129eaf}{-4}}

c=−4

=

−

(

−

5

)

±

(

−

5

)

2

−

4

⋅

6

(

−

4

)

√

2

⋅

6

Step-by-step explanation:

6 0
3 years ago
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