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Andrei [34K]
3 years ago
8

Charlotte has been working for her company for x years. Travis has been working for the same company exactly 3 years longer than

Charlotte. What is the range of the relationship? A. Y ≥ 0 B. Y ≥ 3 C. Y ≤ 3 D. 0 ≤ y ≤ 3
Mathematics
2 answers:
ss7ja [257]3 years ago
6 0

Answer:

D

Step-by-step explanation:

tester [92]3 years ago
4 0

Answer:

i would say c ??

Step-by-step explanation:

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Jon has to pay $7.50 admission for the skating rink and $1.50 per hour to rent rollerblades. Write an equation for the cost (y)
Nata [24]

Answer:

y = 7.50 + 1.50x

Step-by-step explanation:

The admission costs $7.50 and after x hours Jon has to pay $1.50*x. Then the cost y in dollars is

y = 7.50 + 1.50x where x is the number of hours.

4 0
3 years ago
Given f(x) = 10 - 16/x, find all c in the interval [2,8] that satisfy the mean value theorem
Katen [24]
F(x)=10-16/x
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
f'(c)= \frac{f(b)-f(a)}{b-a} in (2,8),
 \frac{16}{c^2} = \frac{f(8)-f(2)}{8-2} ,
 \frac{16}{c^2} = \frac{8-2}{8-2}

4∈[2,8] is the required point.
8 0
4 years ago
Read 2 more answers
Can i pleaseee get help:(
AfilCa [17]

Answer:

Step-by-step explanation:

P=5/25=1/5=0.20

8 0
3 years ago
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A card is selected at random from an ordinary deck of 52 cards. What is the probability that it is either an ace or a spade
tamaranim1 [39]

Answer: 4/13

Step-by-step explanation:

Number of cards in a deck = 52

Number of spades = 13

Number of aces = 4

Number of ace of spade = 1

Probability of either a spade or an ace :

P(spade or ace) = P(spade U ace)

P(spade U ace) = p(spade) + p(ace) - p(spade n ace)

Probability = required outcome / Total possible outcomes

P(spade) = 13 / 52

P(ace) = 4 / 52

P(spade n ace) = 1 / 52

P(spade U ace) = p(spade) + p(ace) - p(spade n ace)

= 13/52 + 4/52 - 1/52

= 16 / 52 = 4 /13

8 0
3 years ago
10 small and 8 large cost $192. 20 small and 1 large cost $99. What is cost of a small
seraphim [82]

Answer:

Step-by-step explanation:

small=s,    s=3.99

large=l,       l=19.20

10s+8l=192.20

20s+l=99

we can see that in the second equation, 20s+l=99

l=99-20s

lets replace l in the first equation

10s+8(99-20s)=192.20

10s+792-160s=192.20

-150s=-792+192.20

150s=599.80

s=3.99

l=99-20(3.99)=99-79.80=19.20

7 0
2 years ago
Read 2 more answers
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