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3 years ago

What's the greatest common factor of 40,80,100

Mathematics

1 answer:

Wewaii [24]3 years ago

8 0

The greatest common factor would be 20

40 80 100
^ ^ ^
2x20 4x20 5x20

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Solve by completing the square 6x-x^2-7

Elden [556K]

−(x^2−6x+7) that is the answer

5 0

3 years ago

A ray of light with intensity lo falls vertically on the sur face of the sea and at ten meters deep its intensity is 10/3. Assum

seropon [69]

Answer:

intensity = $\frac{Io}{15}$

intensity = $\frac{Io}{30}$

depth = 333.33 m

Step-by-step explanation:

given data

deep = 10 m

intensity = Io

intensity = Io/3

to find out

intensity of light at 50 m and 100 m and 1/100 of initial intensity remain ?

solution

we know here that intensity is inversely proportional to deep so

intensity = k × $\frac{1}{Deep}$ .................1

here k is constant

so we have given 10 m deep so

$\frac{Io}{3}$ = $\frac{k}{10}$

so k = Io × $\frac{10}{3}$ ................2

so from equation 1 when 100 m deep and 50 m deep

intensity = k × $\frac{1}{Deep}$

intensity = Io × $\frac{10}{3}$ × $\frac{1}{50}$

intensity = $\frac{Io}{15}$

and

intensity = Io × $\frac{10}{3}$ × $\frac{1}{100}$

intensity = $\frac{Io}{30}$

and

at intensity Io/100

intensity = k × $\frac{1}{Deep}$

$\frac{Io}{100}$ = Io × $\frac{10}{3}$ × $\frac{1}{D}$

D = 333.33 m

so depth = 333.33 m

3 0

3 years ago

WILL UPVOTE PLZ HELP NEED ANSWERS ASAP

Ronch [10]

Arlene; shadow 5ft: 6ft tall. = 5:6
billboard; shadow 35ft: x ft tall = 5:6.
35 * 6 / 5 = 42.
billboard is (C).42ft tall.

5 0

3 years ago

the perimeter of a playing field for a certain sport is 262 ft. the field is a rectangle and the length is 41 ft longer than the

Setler [38]

Answer: The width of the playing field = 45 ft

length of playing fiels = 86ft

Step-by-step explanation:

Step 1

Perimeter of rectangular field is given as 2 ( L+ b)

Let the width be represented as x

such that the length = 41 ft longer than the width be x+ 41

To find the length and breadth

Step 2

Perimeter = 2( L+ b)= 2l + 2b

Perimeter = 2 (x+41 ) + 2 x = 262

2x + 82 + 2x= 262

4x+ 82= 262

4x= 262 - 82

4x= 180

x= 180/4

x= 45

width= 45 ft

length = x+ 41= 45+ 41= 86ft

6 0

3 years ago

I need help with this

mr Goodwill [35]

Answer:

Step-by-step explanation:

Step 1. Calculate the measures of center (mean and median)

Mean= Average= All data values added together then divided by number of data values.

Median = middle of numbers

0: 1
4: 3
5: 8
6: 3
7: 1
8: 5
9: 2

10: 3

So, number of data values = 3+2+5+1+3+8+3+1= 26

Data values added together = 0 + 4+4+4+5+5+5+5+5+5+5+5+6+6+6+7+8+8+8+8+8+9+9+10+10+10= 165

165/26= 6.34615384

Average = 6.3

Median: Arrange numbers from least to greatest and eliminate one on both sides until you get a middle number:

0 , 4,4,4,5,5,5,5,5,5,5,5,6,6,6,7,8,8,8,8,8,9,9,10,10,10

The median is 6.

Step 2: Calculate range, IQR, and MAD

Range: Maximum- minimum

IQR: The IQR is the difference between Q3 and Q1.

Q1 is the middle value in the first half of the data set.

Q3 is the middle value in the second half of the data set.

MAD:

Take the average.
Find the distance of each value from that mean (difference between data values and mean) , then take absolute value of that distance.
Find the mean of those distances.

Range: 10-0= 10

IQR: 3

MAD (population) : 1.9378698224852

MAD (sample) : 1.9378698224852

8 0

4 years ago