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Jobisdone [24]
3 years ago
14

Please help me!!!!!!

Mathematics
2 answers:
Andreas93 [3]3 years ago
6 0

Answer:


Step-by-step explanation:


kvasek [131]3 years ago
4 0

2 would be the correct answer ;-)))) (1 on top?)

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2. Simplify the following expression.<br> – 2(3x – 5) – 12x - 2
aniked [119]

Answer:

-18x+8

Step-by-step explanation:

First you have to distribute the -2 to the 3x and the -5 in the parenthesis giving you -6x+10-12x-2.

Next you combine like terms which gives you -18x+8

3 0
3 years ago
Evaluate 4(-9) i need help lol
PIT_PIT [208]

Answer:

-36

Step-by-step explanation:

How are you in college lol

8 0
3 years ago
Read 2 more answers
Help with this one!!!<br><br><br> Show steps pls :)
Sergeeva-Olga [200]

96\dfrac{11}{20}= 96.55

96.55%=0.9655

95.5845:0.9655=99

Answer: 99

5 0
2 years ago
Read 2 more answers
Which quadrilaterals always have opposite angles that are congruent
horsena [70]

Answer:

(1) Parallelogram A parallelogram is a quadrilateral with two

sets of parallel sides. The opposite or facing sides of a

parallelogram are of equal length, and the opposite angles of a

               

(2) Square

A square is a regular quadrilateral. This means that is has four

equal sides and four equal angles.

(3) Rhombus                                                                                                                                                A rhombus is a quadrilateral whose four sides all have the same

length. Opposite angles of a rhombus have equal measure. The two

diagonals of a rhombus are perpendicular.

(4) Rectangle

A rectangle normally refers to a quadrilateral with four right

angles.

Parallelogram

Step-by-step explanation:

6 0
3 years ago
Solve 2x + 5y = 20; 3x - 10y = 37 by elimination. How do you do this? Thank-you!
mr Goodwill [35]

\left\{\begin{array}{ccc}2x+5y=20&\text{multiply both sides by 2}\\3x-10y=37\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+10y=40\\3x-10y=37\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad7x=77\qquad\text{divide both sides by 7}\\.\qquad\boxed{x=11}\\\\\text{Put the value of x to the first equation:}\\\\2(11)+5y=20\\\\22+5y=20\qquad\text{subtract 22 from both sides}\\\\5y=-2\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{2}{5}}\\\\Answer:\ \boxed{x=11\ and\ y=-\dfrac{2}{5}}

6 0
3 years ago
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