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2 years ago

Find the length of x. Assume the triangles are similar.

Mathematics

1 answer:

Veronika [31]2 years ago

6 0

Answer:

x = 32

Step-by-step explanation:

The longest side is double the length of the shortest side, so x is 2·16 = 32.

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What is the solution to the system of equations?

kobusy [5.1K]

Answer:

The solution I got is (4,2)

Step-by-step explanation:

When I plotted the equations on a graph, they intercepted at (4,2).

3 0

2 years ago

The perimeter of a triangle is 50 mm. The lengths of 2 of the sides are 13.5 mm and 14.5 mm. Find the missing length.

Naddik [55]

The missing side length should be 22. Add 13.5 to 14.5 and you should get 28. Subtract 28 from the total perimeter (50) to get 22.

5 0

2 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago

Help in 5 plz I will give brainlist

elena-14-01-66 [18.8K]

M=14.6 (is rounded to the nearest tenth.)

8 0

3 years ago

-x over 6 -1=-13<br><br><br>show work pleaseee

xenn [34]

Answer:

x=-72

Step-by-step explanation:

-x/6-1=-13

add 1 to both sides

-x/6=-12

multiply 6*-12

-72

x=-72 because -72/6=-12

8 0

3 years ago