The optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
<h3><u>
Solution:</u></h3>
Given that,
<h3><u>The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by:</u></h3>
![d = 1.9[(5.5 \times 10^{-4})l]^{\frac{1}{2}}](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29l%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
where l is the length (in millimeters) of the camera box
<h3><u>Find the optimum pinhole diameter for a camera box with a length of 10 centimeters</u></h3>
l = 10 cm
We know that,
10 cm = 100 mm
<em><u>Therefore, plug in l = 100 in given formula</u></em>
![d = 1.9[(5.5 \times 10^{-4}) \times 100]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-4} \times 10^2]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-2}]^{\frac{1}{2}}\\\\d = 1.9 \times 5.5^{\frac{1}{2} \times 10^{-1}}\\\\d = 0.19 \times 2.345207\\\\d = 0.4455 \approx 0.446](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29%20%5Ctimes%20100%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctimes%2010%5E2%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-2%7D%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%20%5Ctimes%205.5%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2010%5E%7B-1%7D%7D%5C%5C%5C%5Cd%20%3D%200.19%20%5Ctimes%202.345207%5C%5C%5C%5Cd%20%3D%200.4455%20%5Capprox%200.446)
Thus the optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
The answer will be letter C
<h3>
Answer: Trapezoid</h3>
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Explanation:
There are two ways to do this problem.
Method 1 involves listing out the terms until we reach the seventh one.
- square
- hexagon
- trapezoid
- triangle
- square
- hexagon
- trapezoid
- triangle
We see that the trapezoid is term 7.
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Method 2 is faster and the one I recommend.
Since the pattern repeats every 4 items, this means we divide by 4 and look at the remainder. Ignore the quotient entirely.
7/4 = 1 remainder 3
The remainder 3 means that the answer is found in term 3, which is the trapezoid.
Answer:
=−14x+18
Step-by-step explanation:
happy to help ya :)
Answer:
Step-by-step explanation:
Here you go! If you have more like these I recommend using Desmos Graphing calculator :)
