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MariettaO [177]
2 years ago
8

Robert run the 100 meter dash in 13.5. later he run same distance in 10.3 seconds. how many seconds less did it take him to run

the same distance the second time?
Mathematics
1 answer:
leonid [27]2 years ago
3 0

Answer:

3.2seconds

Step-by-step explanation:

Step one:

Robert run the 100 meter dash in 13.5 seconds

We are told that he later  run same distance in 10.3 seconds

Required.

The time difference in the first dash and the second

Step two:

The first dash took 13.5 seconds

the second took 10.3 seconds

the difference = 13.5-10.3= 3.2seconds

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One ordered pair (a,b) satisfies the two equations ab^4 = 12 and a^5 b^5 = 7776. What is the value of 'a' in this ordered pair?
Ivan

Answer:

a = 4.762203156

Step-by-step explanation:

Given:

ab^4 = 12 and a^5b^5 = 7776

Making the equations a subject of a;

a = 12/b^4 and a^5 = 7776/b^5

Finding fifth root on both sides of equation two;

a = \sqrt[5]{7776}/b

You will get a = 6/b

Equating the two equations;

12/b^4 = 6/b

Multiplying both sides by b^4 gives:

b = \sqrt[3]{2} = 1.25992105

We had that a = 12/b^4 so;

a = 12/1.25992105^4 = 12/2.5198421 = 4.762203156

4 0
3 years ago
Find the missing side
Oduvanchick [21]

Answer:

67

Step-by-step explanation:

because the total amount is 180.

so there is 23 +90+x=180so find the number the number is 67

23+90+67=180

5 0
2 years ago
Read 2 more answers
Suppose that $5500 is placed in an account that pays 2% interest compounded each year.
pogonyaev

Answer: After 1 year:    $5,610

After 2 years: $5,722.20

Step-by-step explanation: Use the formula for periodic compounding interest, which is

A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.

Here, P = 5,500, r = 0.02  (that's 2% as a decimal), n = 1,

t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)

Plug the known values in to solve...

For 1 year...

A = 5,500(1 + 0.02/1)^(1*1)

  A = 5,500(1.02)^1

     A = 5,610

For 2 years...

A = 5,500(1 + 0.02/1)^(1*2)

  A = 5,500(1.02)²

     A = 5,722.20

3 0
2 years ago
Exhibit 5-8 The student body of a large university consists of 60% female students. A random sample of 8 students is selected. R
expeople1 [14]

Answer:

P(X=2)=0.04129

Step-by-step explanation:

-This is a binomial probability problem whose function is expressed as;

P(X=x)={n\choose x}p^x(1-p){n-x}

-Given that p=0.6, n=8 , the probability that among the students in the sample exactly two are female is calculated as:

P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X=2)={8\choose2}0.6^2(1-0.6)^6\\\\=0.04129

Hence, the probability of exactly two females is 0.04129

8 0
3 years ago
A total of $98,000 is to be​ invested, some in bonds and some in certificates of deposit​ (CDs). If the amount invested in bonds
mamaluj [8]
B= 2000 + CD
98000 = B + CD
substitute b in
98000 = 2000 + CD + CD
add variables
98000 = 2000 + 2CD
subtract 2000 from each side
96000 = 2CD
divide each side by 2
48000 = CD
7 0
3 years ago
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