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Lapatulllka [165]
3 years ago
5

F(x)=23x+27 

Mathematics
1 answer:
klio [65]3 years ago
7 0
f(x)=23x+27\\
y=23x+27\\
23x=y-27\\
x=\frac{1}{23}y-\frac{27}{23}\\
f^{-1}(x)=\frac{1}{23}x-\frac{27}{23}\\\\
g(x)=12x-d\\
y=12x-d\\
12x=y+d\\
x=\frac{1}{12}y+\frac{1}{12}d\\
g^{-1}(x)=\frac{1}{12}x+\frac{1}{12}d\\\\


\frac{1}{23}(\frac{1}{12}x+\frac{1}{12}d)-\frac{27}{23}=\frac{1}{12}(\frac{1}{23}x-\frac{27}{23})+\frac{1}{12}d\\
\frac{1}{276}x+\frac{1}{276}d-\frac{27}{23}=\frac{1}{276}x-\frac{27}{276}+\frac{1}{12}d\\
\frac{1}{276}d-\frac{1}{12}d=-\frac{27}{276}+\frac{27}{23}=\\
\frac{1}{276}d-\frac{23}{276}d=-\frac{27}{276}+\frac{324}{276}=\\
-\frac{22}{276}d=\frac{297}{276}=\\
-22d=297\\
d=-\frac{297}{22}

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<h2>For a = 1 and b = 10 x+1 and x+2 factors of  x³-ax²-bx-8 = 0</h2><h2>Other factor is (x-4)</h2>

Step-by-step explanation:

We have

                 x³-ax²-bx-8 = 0

Its factors are x+1 and x+2

That is x = -1 and x = -2 are its roots

Substituting x = -1

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Substituting x = -2

               (-2)³-a(-2)²-b(-2)-8 = 0

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Substituting in eqn 1

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The equation is  x³-x²-10x-8 = 0

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So we have

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Other factor is (x-4)

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