Answer:
100 students selected randomly as their enter your middle school in the morning
Step-by-step explanation:
First off, you can rewrite your equation like so: c=(a-b)x. You can then plug in your given constraints for your choices. If a-b = 1 and c = 0 leaving: 0=1(x), x must equal 0 and only 0 as any constant multiplied by 0 equals 0. So that choice is eliminated. Now let's consider when a=b and c != 0. Since we are given a-b and a=b and c != 0, we have:
c = 0x. This contradicts our claim we made about our constraints. C cannot equal zero but we have a-b=0. Therefore, this claim makes no sense as any value for x will not satisfy the equation. This choice is valid. When a=b and c=0, we have: 0 = 0x. Here, x can be any value and still return 0 as an answer. This choice is valid. If a-b=1 and c != 1, we have: c = 1x. Our only rule here is that c cannot equal 1. This means that x can be any value other than 1 so this choice can be marked down. If a != b and c=0, this gives: 0 = (a-b)x. Given that a-b can be any value, x must be equal to only 0 to satisfy this equation so this choice can't be correct. So the right answers are: option 2, option 3, option 4 and option 5.
C
Because that is what you do first
Answer:
so you should add 6 to 13 in case to find 19, then add 6 to 19 to get to 25.
so the first is 13 and we keep adding 6 to get to the answer. we do it 47 times. so we have 13+ (6) (47) = 295 which is the 48th term.
X+y=5
y=x/2 +2
We have to solve this system of equations:
we can solve by substitution method.
y=x/2 +2
x+(x/2 + 2)=5
2x+x+4=10 (lowest common multiplo =2)
3x=10-4
3x=6
x=6/3=2
y=x/2 +2 =2/2 +2=1+2=3
Then:
x=2 and y=3 ⇒(2,3)
Answer: the point is (2,3)
