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melomori [17]
3 years ago
8

3-(2)/(9)b=(1)/(3)b-7

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

b=18

Step-by-step explanation:

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At a restaurant, three salads, two sandwiches, and one drink cost $17.75. One salad, one sandwich, and three drinks cost $10.75.
Leno4ka [110]

Answer:

A salad costs $2.50

A sandwich costs $4.50

A drink costs $1.25

Step-by-step explanation:

Let x represent the salad, y represent the sandwich, and z represent the drink.

Since three salads, two sandwiches, and one drink cost $17.75:

3x + 2y + z = 17.75  (1)

Since one salad, one sandwich, and three drinks cost $10.75:

x + y + 3z = 10.75  (2)

Since a salad costs twice as much as a drink:

x = 2z  (3)

Multiply the equation 2 by -2 then, sum the equation 1 and equation 2:

-2x - 2y - 6z = -21.50

3x + 2y + z = 17.75

→ x - 5z = -3.75

Replace the x with 2z using equation 3:

2z - 5z = -3.75

-3z = -3.75

z = 1.25

x = 2z → x = 2.50

x + y + 3z = 10.75 → 2.50 + y + 3.75 = 10.75 → y + 6.25 = 10.75 → y = 4.50

5 0
3 years ago
Identify the factors of x2 + 25y2. ...?
Sveta_85 [38]
Is the equation like this? x^2 + 25y^2?
If the equation is like that, the answer would be (x-5y)^2 or (x-5y)(x-5y).
how did I get this? Just divide the factors or the get the square root of 25y^2 and it would be 5y. Then just try if it is positive or negative. In this case, it is negative because there is no factor w/ no exponential form. I hopemy answer helped you.
4 0
3 years ago
i need help on a story problem? Jason ran 5/7 of the distance around the school track. Sara ran 4/5 of Jason's distance. What fr
julia-pushkina [17]
The first thing you do is to find the lowest common multiple of 5 and 7.What you do on the bottom, you must do on the top 25/35 / 28/35.  The answer is 25/28.  Sara ran 25/28 of the total distance around the track. 
3 0
3 years ago
10 1/2 * 10 1/2 simplify
Marta_Voda [28]

\frac{441}{4}

change the mixed numbers to improper fractions and multiply the numerators / denominators

10 \frac{1}{2} = \frac{21}{2}

\frac{21}{2} × \frac{21}{2} = \frac{441}{4} = 1110 \frac{1}{4}

4 0
3 years ago
Suppose that A is nonsingular. Prove that its inverse A-1 is unique. [Hint: Show that if there exists two matrices, B and C, suc
Bogdan [553]

Answer with Step-by-step explanation:

Let A is non-singular

\mid A\mid\neq 0

We have to prove that A^{-1} is unique.

Suppose B and C are inverse of A such that

BA=I and AC=I

By using property AA^{-1}=A^{-1}A=I

C=C

(BA)C=B(AC)

I\cdot C=B\cdot I

C=B

Hence, the inverse of A is unique.

4 0
3 years ago
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