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Dimas [21]
3 years ago
14

Reposted

Mathematics
2 answers:
mihalych1998 [28]3 years ago
8 0
The equation, y=4x+15 represents the relationship shown in the graph.
Finger [1]3 years ago
4 0

Answer:

4. -4x+y=15

Step-by-step explanation:

We have been given a graph of a linear function and we are asked to find the correct equation representing the relationship shown in the graph.

Since we know that the standard form of an equation is in form: Ax+By=C, where A, B and C are integers.

First of all we will find the slope of our line and write equation of line in slope-intercept form. Then we will change it into standard form.

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{23-15}{2-0}

m=\frac{8}{2}=4

Slope of our line is 4. We can see that y-intercept (b) is 15. Now let us write equation of our line in slope-intercept form.

y=mx+b

y=4x+15

Now we will change our given equation into standard form by subtracting 4x from both sides of our equation.

-4x+y=4x+15-4x

-4x+y=15    

Therefore, the equation -4x+y=15 represents the relationship shown in the graph in standard form and 4th option is the correct choice.



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Task 1:
OleMash [197]

Answer:

maximum height is 4.058 metres

Time in air = 0.033 second

Step-by-step explanation:

Given that the equation height h

h = -212t^2 + 7t + 4

What is the toy's maximum height?

Let us assume that the equation is a perfect parabola

Time t at Maximum height will be

t = -b/2a

Where b = 7 and a = - 212

t = -7/ - 212 ×2

t = 7/ 424 = 0.0165s

Substitute t in the main equation

h = - 212(7/424)^2 + 7(7/424) + 4

h = - 0.05778 + 0.115567 + 4

h = 4.058 metres

Therefore the maximum height is 4.058 metres

How long is the toy in the air?​

The object will go up and return to the ground.

At ground level, h = 0

-212t^2 + 7t + 4 = 0

212t^2 - 7t - 4 = 0

You can factorize the above equation and pick the positive time t since time can't be negative

Or

Since we have assumed that it's a perfect parabola,

Total time in air = (-b/2a) × 2

Time in air = 0.0165 × 2 = 0.033 s

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