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3 years ago

3 With 72 million bicycles, correct to the

Mathematics

1 answer:

Galina-37 [17]3 years ago

5 0

Answer:

181 million km

Step-by-step explanation:

"Correct to the nearest unit" means the actual value might be 1/2 unit larger (or smaller) than the reported value.

The upper bound would be the product of the maximum number of bicycles and the maximum distance each travels:

(72.5 · 10^6 bicycles)(2.5 km/bicycle) = 181.25 · 10^6 km

Since the given numbers are good to 2 significant figures (or so), we might reasonably put the upper bound as 180·10^6 km.

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Solve

Katena32 [7]

Answer:

${(5xy)}^{ - 4} = \frac{1}{ {(5xy)}^{4} } = \frac{1}{ {(5 \times 3 \times 2)}^{4} } \\ \\ \\ \frac{1}{ {(30)}^{4} } = \frac{1}{810000} = 1.23 \times {10}^{ - 6}$

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2 years ago

Given that lines a and b are parallel, what angles formed on line b when cut by the transversal are congruent with ∠2?

Kruka [31]

Answer:

The angles formed on line b when cut by the transversal are congruent with ∠2 are $\angle{6}\text{ and }\angle{7}$

Step-by-step explanation:

Consider the provided information.

If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .

The angles on the same corners are called corresponding angle.

Alternate Angles: Angles that are in opposite positions relative to a transversal intersecting two lines.

∠2 and ∠6 are corresponding angles

Therefore, ∠2 = ∠6

∠2 and ∠7 are alternate exterior angles

Therefore, ∠2 = ∠7

Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are $\angle{6}\text{ and }\angle{7}$

3 0

3 years ago

Factor over the complex numbers: 36x2 + 9.

ludmilkaskok [199]

$36x^2+9=(6x)^2-(-9)=(6x)^2-(-3^2)\\\\=(6x)^2-(3i)^2=(6x-3i)(6x+3i)\\\\\text{Used:}\\a^2-b^2=(a-b)(a+b)\\\\i^2=-1$

4 0

3 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

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3 years ago

Triangle ABC is similar to triangle CDE. Both are right triangles. Which statements about the two triangles must be true? Choose

Eddi Din [679]

The question ask to choose among the choices that states the truth about the triangle ABC and triangle CDE which is they are similar. The statement that tells the truth is letter C. Triangle ABC is congruent to triangle CDW and also D. Side AC is congruent it side CE. I hope this will help

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3 years ago