Four hundred meters of fencing is provided to fence three sides of a rectangular pasture. One side is bounded by an existing wal
l. What is the maximum area that can be enclosed?
1 answer:
150x100= 15,000 square meters
150x2= 300
100 + 300 = 400 meters of fencing
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The answer to the math problem is 10.35
Answer:
y ≥−3
Step-by-step explanation:
1 By inspecting the graph, the range is:
y\ge -3y≥−3
Done
What is y+x?
Answer:
<span>= <span>x+<span>y</span></span></span>
That should be the answer
3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5
