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Dmitriy789 [7]
2 years ago
7

110,568÷220−568÷220 Calculate efficiently in your head.

Mathematics
2 answers:
julsineya [31]2 years ago
8 0

Answer:

500?

Step-by-step explanation:

AveGali [126]2 years ago
3 0

Answer:

  500

Step-by-step explanation:

Mental calculation often makes use of factoring and cancelling of factors. To the greatest possible extent, multiplying or dividing by powers of 2, 5 and 10 are also used.

  \dfrac{110568}{220}-\dfrac{568}{220}=\dfrac{110568-568}{220}=\dfrac{110000}{220}\\\\=\dfrac{110}{220}\cdot1000=\dfrac{1}{2}\cdot1000=\boxed{500}

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The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi
tiny-mole [99]

Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

(c)0.83

(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|

(a)Probability distribution for the job satisfaction score of a senior executive.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|

(b)Probability distribution for the job satisfaction score of a middle manager.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

=f_2(5)\\=0.28

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Step-by-step explanation:

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