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alexandr402 [8]
3 years ago
10

Suppose Carol Danvers invested $1,000 into an account paying 6% annual interest compounded

Mathematics
1 answer:
Jet001 [13]3 years ago
6 0

Answer:

$ 1,060.00

Step-by-step explanation:

A = $ 1,060.00

A = P + I where

P (principal) = $ 1,000.00

I (interest) = $ 60.00

Compound Interest Equation

A = P(1 + r/n)^nt

Where:

A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

R = Annual Nominal Interest Rate in percent

r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

n = number of compounding periods per unit t; at the END of each period

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Answer:

value of a.b = -4

Step-by-step explanation:

We need to find a.b

a= 4i-4j

b = 4i+5j

We know that i.i =1, j.j=1, i.j =0 and j.i=0

a.b = (4i-4j).(4i+5j)

a.b = 4i(4i+5j)-4j(4i+5j)

a.b = 16i.i +20i.j-16j.i-20j.j

a.b = 16(1) +20(0)-16(0)-20(1)

a.b = 16 +0-0-20

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So, value of a.b = -4

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Answer:

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Please help it's for a test!
Tanya [424]

Answer:

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Step-by-step explanation:

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then        0.01          ⇒   0.0019

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we find x =  0.00095

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Step-by-step explanation:

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