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3 years ago

Graph y<1−3x . Please only answer if you know what you're doing

Mathematics

1 answer:

Tema [17]3 years ago

3 0

y < 1 - 3x can alse be written as y < -3x + 1 (which crosses the y-axis at 1 and has a slope of -3 (aka rise over run of: down 3 and to the right 1)

The symbol (<) represents a dashed line that is shaded below.

Answer: A

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3 years ago

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A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

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The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

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$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

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$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

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Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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Graph ​ y<1−3x ​. Please only answer if you know what you're doing

Graph y<1−3x . Please only answer if you know what you're doing