<h3>
Answer: a = -1 (fourth choice)</h3>
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Work Shown:
q = (-4, 1) is one vector
r = (a,3) is another vector
The resultant vector is
q+r = (-4,1)+(a,3)
q+r = (-4+a,1+3)
q+r = (-4+a,4)
Multiply both sides by 7
7(q+r) = 7*(-4+a,4)
7(q+r) = (7*(-4+a),7*4)
7(q+r) = (-28+7a, 28)
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Since 7(q+r) = (-35, 28), we know that,
(-28+7a, 28) = (-35, 28)
which leads to
-28 + 7a = -35
when we equate the x components of each vector. Let's solve for 'a'
-28 + 7a = -35
7a = -35+28
7a = -7
a = -7/7
a = -1
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Check:
q = (-4,1)
r = (a,3) = (-1,3)
q+r = (-4,1)+(-1,3)
q+r = (-4+(-1), 1+3)
q+r = (-5, 4)
7*(q+r) = 7*(-5, 4)
7*(q+r) = (7*(-5), 7*4)
7*(q+r) = (-35, 28)
The answer is confirmed.
Answer:
x=5
Step-by-step explanation:
multipy both sides of the equation by 3 to remove the denominator becomes
2+5x=27
subtract 2 from both sides since it's positive
5x=25
divide 5 from both sides
x=5
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Answer:
3(x + 2)
Step-by-step explanation:
Answer: The required equation is 
and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be
Now, add 52 on both the sides of the equation, we get
Can you post the provable question
