San was a 1074774 minute walk
18 girls
Half of the students volunteer
15 don't -- so the other half must be 15 as well making there 30 students in the class.
If 12 are boys, then 30(students in class) - 12 (boys) = 18 girls
<span>The answer is 0.00001267 m = 1.267 * 10^(-5) m. In scientific notation, the number is written as two factors - a number m from 0-10 and 10 raised to the n power: m x 10^n. 0.00001267 m = 1.267 x 0.00001 m. 0.00001 m = (0.1)^5 = 10^(-5). So: 0.00001267 m = 1.267 x 0.00001 m = 1.267 x (0.1)^5 m = 1.267 x 10^(-5) m.</span>
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
yes
Step-by-step explanation: