At a telethon, a volunteer can take 48 calls over a 4-hour shift. At this rate, how many calls can 12 volunteers take in a 4-hou
1 answer:
You might be interested in
Answer:
2.99 cm²
Step-by-step explanation:
<em>(The "..." at the end of the decimal means that number is repeating)</em>
The perimeter of a rectangle is the length around the shape. The equation for a rectangle's perimeter is L + W × 2, with L and W representing length and width, respectively (You multiply the length and width by two because the shape is four-sided, so it has two length sides and two width sides). To find the area of the rectangle, you need to know the individual length and width, so you'll solve for that first.
Since you're only given the perimeter and you know the length is double the width, you'll need to work backwards with this equation. To do this, first divide the perimeter (7 , also written as 7.33...) by 2; this equals 3
, also written as 3.66...
Next, you can find the length and width by determining what two numbers multiply to equal 3.66..., with one number being two times larger than the other number. The way I tend to think of this is that if one number is double the other, then the smaller number is one third of the sum of the two numbers (since the smaller number represents one part of the sum, and the other represents two parts of the sum, which is double the smaller number).
Since the length and width combine to be the divided perimeter, 3.66..., that means two thirds of 3.66... is the longer side (the length), and then the one third of 3.66... is the shorter side (the width). This means the length is 2.44... and the width is 1.22...
Finally, you can solve for the perimeter by dividing the perimeter by two and then subtracting the length squared. The written equation looks like this:
A = P - L²
(A = area, P = perimeter, L = lenth)
Now just insert the numbers into the equation and solve!
The area of the rectangle is 2.99cm²
Answer:
The velocity of jet in still air is and velocity of wind is
.
Step-by-step explanation:
Let x be the rate of the jet in still air and y be the rate of the wind.
Given:
Velocity against wind, a jet travels 2160 miles in 3 hours.
Velocity against wind
Flying with the wind, same jet travels 6000 miles in 6 hours.
Flying with the wind
As such its velocity against wind is
and with wind is
therefore
------------(1)
---------------(2)
Adding equation 1 and 2.
Put x value in equation 2
Hence velocity of jet in still air is and velocity of wind is
.