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gizmo_the_mogwai [7]

3 years ago

12

At the beginning of March, a store bought a fancy watch at a cost of $250 and marked it up 20%. At the end of the month, the fan

cy watch had not sold, so the store marked it down 10%. What was the discounted price?

1 answer:

alexandr402 [8]3 years ago

7 0

Answer:

$270

Step-by-step explanation:

Price after markup was 1.20($250) = $300

Price after discounting: (1.00 - 0.10)($300) = $270

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What is the value of x in the figure? Enter your answer in the box.<br> 145°<br> (2x + 15)°<br> x=

Nikolay [14]

Answer:

Answer: x=65

Step-by-step explanation:

Since they're vertical angles both sides are equal to 145 degrees

So, 145-15= 130 to get rid of the constant

Then, 130/2=65

To check you work add up all of your solutions to get 145

2*65=130 & 130+15=145

Therefore, x=65

8 0

3 years ago

Read 2 more answers

Find the difference: 11 - 4.7

shutvik [7]

<u><em>Answer: 6.3 *The answer must be have a decimal point.*</em></u>

Explanation:

First, subtract by the numbers. Subtract it's going to be find the difference between the numbers.

$11-4.7=6.3$

You can also add by the numbers.

$6.3+4.7=11$

$11-6.3=4.7$

Hope this helps!

Thank you!

Have a great day!

7 0

3 years ago

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Suppose you are traveling straight from Los Angeles, California to Albuquerque, New Mexico, stopping overnight in Flagstaff, Ari

Roman55 [17]

<span>D. L.A. to Flagstaff, 465 miles; Flagstaff to Albuquerque, 345 miles

The answer above is correct.

810 - 120 = 690 ; 690 / 2 = 345 mi ( Flagstaff to Albuquerque )

810 - 345 = 465 mi ( L.A. to Flagstaff )

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3 0

3 years ago

Two thirds of the families in smithville own their own homes. The total number of home owning families there is 480. How many fa

Leviafan [203]

X- the total number of families in Smithville<span>.
(2/3)x - the number of home owning families.
At the same time, </span> the number of home owning families is 480.

(2/3)x=480
x=480*3/2=720.

720 <span>families live in Smithville.</span>

8 0

3 years ago

You have a garden in your backyard that measures 15 meters by 20 meters. You want to place stepping stones around the perimeter

Anettt [7]

Answer:

0.5 m

Step-by-step explanation:

Given that the dimensions of the garden are 15 meters by 20 meters.

The area of the new garden (original garden + stone placed around the perimeter) is 336m².

Let d be the width of the border having stepping stones as shown in the figure. The shaded region in the figure is the area having stepping stones.

The area including the shaded region $= (15+2d)(20+2d) m^2$

$\Rightarrow 336 = (15+2d)(20+2d) \\\\\Rightarrow 336 = 300+ 70 d +4d^2 \\\\\Rightarrow 4d^2 +70d+300-336=0 \\\\\Rightarrow 4d^2 +70d-36=0 \\\\\Rightarrow 2d^2 +35d-18=0 \\\\\Rightarrow 2d^2 +36d-d-18=0 \\\\\Rightarrow (2d-1)(d+18)=0 \\\\\Rightarrow (2d-1)=0, \; or \; (d+18) \\\\\Rightarrow d= 0.5\;or -18 \\\\$

As the width of the stone border can't be a negative value, so taking the positive value.

Hence, the width of the stone border is 0.5 m.

So, the wi

7 0

3 years ago