Ask question

Ask question

All categories

gizmo_the_mogwai [7]

3 years ago

12

At the beginning of March, a store bought a fancy watch at a cost of $250 and marked it up 20%. At the end of the month, the fan

cy watch had not sold, so the store marked it down 10%. What was the discounted price?

1 answer:

alexandr402 [8]3 years ago

7 0

Answer:

$270

Step-by-step explanation:

Price after markup was 1.20($250) = $300

Price after discounting: (1.00 - 0.10)($300) = $270

You might be interested in

Help asap please!!!!!!

Andrews [41]

Step-by-step explanation:

[(-3 × 2 × (-4)] ÷ [-6 × 12]

[3 × 2 × -4] ÷ [-6 × 12]

[6 × -4]/[-6 × 12]

-4/(-1 × 12]

-4/-12

⅓

Option A is wrong

Option B is wrong -9/-18 = ½ not ⅓

Option C is correct = -24/-72 = ⅓

Option D is wrong = 9/-18 = -½ not ⅓

3 0

3 years ago

Help me please <br> !!!!!!!!!!!!!!!

Vitek1552 [10]

16 units. Start from -2 and count up to 14. Basically -2+2+2+2+2+2+2+2+2+2 since the scale is by 2

4 0

3 years ago

Which congruence postulate is this? SAS, SSS, AAS, ASA, HL

lara31 [8.8K]

Answer:

SAS

Step-by-step explanation:

6 0

2 years ago

a photographer is taking the 4th grade class picture. She stands on a ladder to get a better angle . From the top step of the la

Kruka [31]

Given:
a ladder with three steps.
top step is 45° angle.

45° / 3 steps = 15°

So, top step is 45°. Middle step is 30°. Bottom step is 15°. Ground is 0°

The photographer would shout on the bottom step at an angle of 15°.

4 0

3 years ago

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$

$P(20 \leq x \leq 30) =99.84\%$

5 0

3 years ago