Find the solution to the following equation by transforming it into a perfect square trinomial.* x2 + 2x = 8

2 answers:

6 0

$x^{2} +2x=8 \ add \ 1 \ to \ both \ sides\\
\\
 x^{2} +x+8+1 \ in \ the \ left \ side \ you \ find \ a perfect \ square \ trinomial\\
\\
(x+1)^2=9\\
\\
So:\\
\\
x+1=\pm \sqrt{9}\\
\\
x+1=\pm 3\\
\\
 x+1=3 \rightarrow x=2\\
\\
x+1=-3 \rightarrow \x=-4$

aleksklad [387]3 years ago

6 0

X2+2x-8 =0
x2 + 4x - 2x - 8 = 0
x(x+4) - 2(x+4) = 0
(x-2)(x+4) = 0
let x- 2 = 0
x = 2
let x+4 = 0
x= -4

You might be interested in

Use the point-slope formula to write an equation of the line that passes through (4,10) and has a slope of m= 3. Write the

baherus [9]

Answer:
3x --y -2= 0
Step-by-step explanation:
We have formula Y - y 1 = m ( X --x1) => Y - 10 = 3(X-4)
3X - Y - 2 = 0 Ans .

4 0

2 years ago

Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

Recall:

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things