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Reil [10]
2 years ago
8

Find the solution to the following equation by transforming it into a perfect square trinomial.* x2 + 2x = 8

Mathematics
2 answers:
andriy [413]2 years ago
6 0
x^{2} +2x=8 \ add \ 1 \ to \ both \ sides\\
\\
 x^{2} +x+8+1 \ in \ the \ left \ side \ you \ find \ a perfect \ square \ trinomial\\
\\
(x+1)^2=9\\
\\
So:\\
\\
x+1=\pm  \sqrt{9}\\
\\
x+1=\pm 3\\
\\
 x+1=3 \rightarrow x=2\\
\\
x+1=-3 \rightarrow \x=-4
aleksklad [387]2 years ago
6 0
X2+2x-8 =0
x2 + 4x - 2x - 8 = 0
x(x+4) - 2(x+4) = 0
(x-2)(x+4) = 0
let x- 2 = 0
x = 2
let x+4 = 0
x= -4
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Step-by-step explanation:

Here it's given that ,

\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}

Also ,

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So , on substituting the respective values to find s we have ,

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\sf\red{\longrightarrow}A = 3*2\\

\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}

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