Question

Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59

Answer 1

Answer:

The sum of 10 terms G.P is 310.                                                

Step-by-step explanation:

We are given the following in the question:

There are 10 terms in a geometric series.

First term, a = 3

Last term = 59

$a_{10} = 59$

Sum of n terms of a geometric progression is given by:

$S_n = \dfrac{n(a+a_n)}{2}$

Putting the values, we get,

$S_{10} = \dfrac{10(3+59)}{2} = 310$

Thus, the sum of 10 terms G.P is 310.