The length would be 30 feet, and the width would be 10 feet.
<span>2x^2 - 2x - 1 = 0 a = 2, b = -2, c = -1 b^2 - 4ac = (-2)^2 - 4(2)(-1) = 4 + 8 = 12
so the answer is 12
</span>
Answer:
B. Gaining
Step-by-step explanation:
Answer:
The option "The function has a positive y-intercept" is true because f(0) = 2, which is the y-intercept.
Step-by-step explanation:
The valid conclusions for the manager based on the considered test is given by: Option
<h3>When do we perform one sample z-test?</h3>
One sample z-test is performed if the sample size is large enough (n > 30) and we want to know if the sample comes from the specific population.
For this case, we're specified that:
- Population mean =
= $150 - Population standard deviation =
= $30.20 - Sample mean =
= $160 - Sample size = n = 40 > 30
- Level of significance =
= 2.5% = 0.025 - We want to determine if the average customer spends more in his store than the national average.
Forming hypotheses:
- Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get:
![H_0: \mu_0 \leq \mu = 150](https://tex.z-dn.net/?f=H_0%3A%20%5Cmu_0%20%5Cleq%20%5Cmu%20%3D%20150)
- Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically
![H_1: \mu_0 > \mu = 150](https://tex.z-dn.net/?f=H_1%3A%20%5Cmu_0%20%3E%20%5Cmu%20%3D%20150)
where
is the hypothesized population mean of the money his customer spends in his store.
The z-test statistic we get is:
![z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094](https://tex.z-dn.net/?f=z%20%3D%20%5Cdfrac%7B%5Coverline%7Bx%7D%20-%20%5Cmu_0%7D%7B%5Csigma%2F%5Csqrt%7Bn%7D%7D%20%3D%20%5Cdfrac%7B160%20-%20150%7D%7B30.20%2F%5Csqrt%7B40%7D%7D%20%5Capprox%202.094)
The test is single tailed, (right tailed).
The critical value of z at level of significance 0.025 is 1.96
Since we've got 2.904 > 1.96, so we reject the null hypothesis.
(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).
Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.
Learn more about one-sample z-test here:
brainly.com/question/21477856