Ask question

Ask question

All categories

3 years ago

7

In the xy -plane above, point C has coordinates (6, 9). Which of the following is an equation of the line that contains points O

and C ?

1 answer:

lilavasa [31]3 years ago

8 0

The xy-plane is so far above that it's not visible,
and we can't see where point-O is.

You might be interested in

Solve the system of equations by the substitution method:<br> 4x-y = 35<br> 7x + 6y = 38

Leokris [45]

Answer:

x=8 and y=−3

8 0

2 years ago

The price of a bicycle was increased from $300 to $450. What percent of the original price is the increased price?

mezya [45]

It increased with 150%

7 0

3 years ago

a certain medicine is given in an amount proportional to a patient's weight. patient weighs 159 pounds requires 212 miligrams of

Montano1993 [528]

159÷212=0.75
0.75×129= 172

7 0

2 years ago

Use technology to solve for x. 2x−8=3x−9 What are the solutions?

deff fn [24]

Step-by-step explanation:

$2x - 8 = 3x - 9 \\ \\ \therefore \: 9 - 8 = 3x - 2x \\ \\ \therefore \: 1 = x \\ \\ \therefore \: x = 1$

3 0

3 years ago

Todd and his brother Robert are going to use 512 square feet of their backyard for skateboard ramps. The shape of the backyard i

Fiesta28 [93]

Answer:

The dimensions are $16$ ft by $32$ ft

The quadratic equation is $W^{2}-256=0$

Step-by-step explanation:

we know that

the area of rectangle is equal to

$A=W*L$

where

L is the length side of rectangle

W is the width side of rectangle

in this problem

we have

$A=512\ ft^{2}$

so

$512=L*W$ -----> equation A

$L=2W$ ------> equation B

substitute equation B in equation A

$512=(2W)*W \\ 512=2W^{2} \\2W^{2}-512=0\\W^{2}-256=0$

$W=\sqrt{256}=16\ ft$

Find the value of L

$L=2W-----> L=2*16=32\ ft$

7 0

3 years ago

Read 2 more answers