Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
Answer:
Explained below.
Step-by-step explanation:
The formula for the interior angle of any regular polygon is given as;
Interior Angle = 180(n - 2)/n
Where n is number of sides
We are told the interior angle is 40°
Thus;
180(n - 2)/n = 40
Cross multiply to get;
180n - 360 = 40n
180n - 40n = 360
140n = 360
n = 360/140
n = 2.57
Number of sides of a regular polygon cannot be in decimal nor can it have less than 3 sides.
Thus, a shape with interior angle of 40 cannot be a polygon.
Start at (0, 72), then (1, 64), (2, 56), ETC. I hope you see the pattern! Do it until you reach (9, 0)
Start off with: 5 1/6 - 1 5/9
turn it into an entire fraction: 31/6 - 14/9
make a common denominator (which is 18): 93/18 - 28/18 = 93 - 28 = 65/18
65/18 + 7 2/3 is the new equation
7 2/3 = 23/3
23/3 = 138/18
65/18 + 138/18 = 203/18
Simplify: 203/18 = 11 5/18
Answer: 11 5/18
