Please help with mathimatics

Help me please I need help

cluponka [151]

Answer:

A=5, B=3y

Step-by-step explanation:

Please see attached picture for full solution

3 0

3 years ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books off the edge.

krok68 [10]

Answer:

Josh's book lands first
Ben's lands about 0.648 seconds later

Step-by-step explanation:

Using the given equation for v=60 and s=40, the height of Ben's book is ...

h(t) = -16t² +60t +40

We want to find t when h(t) = 0, so we're looking for the solution to ....

0 = -16t² +60t +40

Using the quadratic formula, we find the positive value of t to be ...

t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277

__

Similarly, the height of Josh's book is ...

0 = -16t² +48t +40

t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794

__

The time before Josh's book lands is shorter by ...

4.3277 -3.6794 ≈ 0.6482 . . . . . seconds

Josh's book reaches the ground first, by about 0.648 seconds.

3 0

2 years ago

Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

6 0

3 years ago

Read 2 more answers

What is the value of m in the figure below?

Scilla [17]

Answer:

Step-by-step explanation:

6.7

6 0

3 years ago

Bonus: In Triangle STP, the measure of <T is twice the measure of <S and the

olganol [36]

Answer:

m∠S=30°

m∠T=60°

m∠P=90°

Step-by-step explanation:

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

so

In the triangle STP

m∠S+m∠T+m∠P=180° ----> equation A

m∠T=2(m∠S) ----> equation B

m∠P=3(m∠S) ----> equation C

Solve the system of equations by substitution

Substitute equation B and equation C in equation A

m∠S+2(m∠S)+3(m∠S)=180°

Solve for m∠S

6m∠S=180°

m∠S=30°

m∠T=2(m∠S)

m∠T=2(30°)=60°

m∠P=3(m∠S)

m∠P=3(30°)=90°

3 0

2 years ago