Answer:
Step-by-step explanation:
Hello,
degree 5
4 is a zero of multiplicity 3 -> (x-4)^3 is a factor
-4 is the only other zero, so the multiplicity is 5-3=2 -> (x+4)^2 is a factor
leading coefficient is 4 so we can write
![\boxed{4(x-4)^3(x+4)^2}](https://tex.z-dn.net/?f=%5Cboxed%7B4%28x-4%29%5E3%28x%2B4%29%5E2%7D)
If there is something that you do not understand or you are blocked somewhere let us know what / where.
Thank you.
C=2πr r radius it would be right
Answer:
Rate of change = 3
Step-by-step explanation:
The rate of change is the slope.
Slope = 3
She should have added 2 to both sides of the equation instead of subtracting 2.
2x -2 = 14
Add 2 to both sides:
2x = 16
Divide both sides by 2:
x = 8
Answer:
![x =320](https://tex.z-dn.net/?f=x%20%3D320)
Step-by-step explanation:
Given
![x^2 + 200x = 166400](https://tex.z-dn.net/?f=x%5E2%20%2B%20200x%20%3D%20166400)
Required
Find x
We have:
![x^2 + 200x = 166400](https://tex.z-dn.net/?f=x%5E2%20%2B%20200x%20%3D%20166400)
Rewrite as:
![x^2 + 200x - 166400 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%20200x%20-%20166400%20%3D%200)
Expand
![x^2 + 520x - 320x - 166400 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%20520x%20-%20320x%20-%20166400%20%3D%200)
Factorize
![x(x + 520) - 320(x + 520)= 0](https://tex.z-dn.net/?f=x%28x%20%2B%20520%29%20-%20320%28x%20%2B%20520%29%3D%200)
Factor out x + 520
![(x - 320) (x + 520)= 0](https://tex.z-dn.net/?f=%28x%20-%20320%29%20%28x%20%2B%20520%29%3D%200)
Split
![x - 320 = 0\ or\ x + 520= 0](https://tex.z-dn.net/?f=x%20-%20320%20%3D%200%5C%20or%5C%20x%20%2B%20520%3D%200)
Solve
![x = 320\ or\ x =- 520](https://tex.z-dn.net/?f=x%20%3D%20320%5C%20or%5C%20x%20%3D-%20520)
Side length must be positive;
So:
![x = 320](https://tex.z-dn.net/?f=x%20%3D%20320)